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I am Lyosha [343]
2 years ago
8

Please Help!!!!!!!!!!

Mathematics
1 answer:
timama [110]2 years ago
6 0

Answer:

the answer is b

Step-by-step explanation:

the answer is b

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Solving a right triangle (round to the nearest tenth)
Inga [223]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

----------------------------------------------------------------

tan46° = \frac{opposite}{adjacent} = \frac{b}{23}

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

-----------------------------------------------------------------

cos46° = \frac{adjacent}{hypotenuse} = \frac{23}{c}

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c = \frac{23}{cos46} ≈ 33.1 ( to the nearest tenth )

5 0
3 years ago
The Choi family wants to save money to travel the world. They purchase an annuity with a monthly payment of $65 that earns 4.5%
Lesechka [4]

Answer:

You can get an idea of how much guaranteed lifetime income a given amount of savings will buy by going to this annuity payment calculator. Today, for example, $100,000 would get a 65-year-old man about $525 a month in lifetime income, while that amount would generate roughly $490 a month for a 65-year-old woman.

8 0
3 years ago
Read 2 more answers
Please help with this question please
puteri [66]

Answer:

Choice A

Step-by-step explanation:

(4m^5n^2/m^2n)^3

dividing exponents = subtraction

(4m^3n)^3

4^3 = 64

(m^3 )^3 = m^3x3 = m^9

64m^9n^3

5 0
3 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4



draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
Hello Pls help and thanks
Anna11 [10]

Answer:

c.) in the correct answer

6 0
3 years ago
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