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Naddik [55]
3 years ago
10

$29.99 markdown 33 and one third

Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
Original Price: $29.99
Mark down: 33 1/3%
Mark down Price: $20.00

29.99 * 33 1/3 = 29.99 * 0.3333 = 9.99 value of mark down.
29.99 - 9.99 = 20.00 new price.

The problem is not really clear. We can assume that $29.99 is the mark down price. We need to look for the original price.

Mark down price: $29.99
Mark down rate : 33 1/3%
Original Price    : $44.98

29.99 / ((100% - 33 1/3%) / 100%) = 29.99 / ( 66 2/3% / 100%)
29.99 / 0.6667 = 44.98
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Given:
Equilateral triangle: height = 2.6 inches ; base or side length = 3 inches
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1 name plate has 2 equilateral triangle and 3 rectangles.
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18 in² x 3 = 54 in²

7.8 in² + 54 in² = 61.8 in²

61.8 in² x 30 nameplates = 1,854 in²  Choice A.
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Find the surface area of the prism.
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Which is the graph of the following inequality?
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D) graph D

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2 years ago
Suppose we write the numbers $1,2,3,4,5,6$, and then color each number red or blue. The coloring is called factorific if there i
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Answer:

The probability that his coloring is factorific is 0.28125

Step-by-step explanation:

For calculate the probability is necessary to identify the total number of ways to color the six number. This can be calculate with the rule of multiplication as:

2*2*2*2*2*2=64

Because we have 2 options to color every number.

For know the number of ways in which the coloring is factorific, first we need to identify the divisors of each number:

1: the divisor is 1

2: The divisors are 2 and 1

3: The divisors are 3 and 1

4: The divisors are 4, 2 and 1

5: The divisors are 5 and 1

6: The divisors are 6, 3 and 1

From these information we analyse that for made a factorific coloring, is necessary that the number 1 is color blue. Additionally if the number 4 is color blue, the number 2 needs to be color blue and if the number 6 is blue, the number 3 needs to be blue.

So, the number of ways in which we can create a factorfic number is determined by the following cases:

  • The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    2          </u>=   8

number 1    number 2    number 3   number 4  number 5  number 6

At the same way we can calculate the following cases:

  • The number 2 is blue and the number 3 is red:  If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    1          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is red:  If the number 2 and 3  are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>           1   </u>  *<u>         2    </u>* <u>    1          </u>=  2

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is blue:  If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          1   </u>  *<u>         2    </u>* <u>    2          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

P= \frac{18}{64} =  0.28125

4 0
3 years ago
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