One of the two equations required in the system of equations needed to determine the dollar amount of phone and computer sales Houa made is y = x + 600.
<h3>How do we write the system of equations?</h3>
Let x represents the dollar amount of phone sales Houa made, and y represents the dollar amount of computer sales she made.
Therefore, a system of equations that could be used to determine x and y can be written as follows:
y = x + 600 ........................................................... (1)
0.04x + 0.05y = 129 ......................................... (2)
Learn more about the system of equations here: brainly.com/question/21620502.
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All you have to do here is convert the mixed number measurements to inches. Because there are 12 inches in a foot, 5ft. 3in. becomes 63 inches. 2ft. 8in. becomes 32 inches. 63-32=31 inches, which is 2ft. 7in.
-2|-2r-4|=-12
divide by -2
|-2r-4| = 6
we get a positive and negative solution
-2r-4 = 6 and -2r - 4 = -6
-add 4 to each side
-2r = 10 -2r = -2
divide by -2
r = -5 and r = 1
Answer r = -5 ,1
Answer:
0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of $0.35 and a standard deviation of $0.33.
This means that
.
What is the probability that a randomly selected stock will close up $0.75 or more?
This is 1 subtracted by the p-value of Z when X = 0.75. So



has a p-value of 0.8869.
1 - 0.8869 = 0.1131
0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.