Ask question

Ask question

All categories

4 years ago

11

Rewrite the rational exponent as a radical expression 2 and 7 over 8 and 2 and 1 over 4

1 answer:

VashaNatasha [74]4 years ago

6 0

Convert to improper frist
2 and 7/8=16/8+7/8=23/8
2 and 1/4=8/4+1/4=9/4

(23/8)/(9/4)
make bottom 1
times the whole thing by (4/9)/(4/9)
(92/72)/(36/36)=
92/72=
23/18

You might be interested in

How do you write 23.5% as a decimal?

vesna_86 [32]

Answer:0.235

Step-by-step explanation:

Take the decimal point and move it to the left twice and you get your answer

3 0

3 years ago

Read 2 more answers

If you need to use 4/5 of a cup of strawberries for a single pie . How many cups would be needed for 2 pies.

kirza4 [7]

Answer:

1 3/5 or 8/5 cups for 2 pies

Step-by-step explanation:

5 0

3 years ago

Please answer correctly !!!!! Will mark brainliest answer !!!!!!!!!!

AnnZ [28]

Answer:

type 2 in the first box,

13/4 in the second box, and

-9/8 in the third one

Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:

$x_{vertex}= -b/2a$

Which in our case is: -13/4

and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:

$f(-13/4)= -9/8$

Then your expression for this quadratic should be:

$f(x)=2\,(x+\frac{13}{4} )^2+(-\frac{9}{8})$

Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one

7 0

3 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

3 years ago

Students have a height is less than what number 58?62?64?70?

olya-2409 [2.1K]

Answer:

C 64 students have half the height

7 0

3 years ago