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3 years ago

5

What is the missing base 256 = ^4

1 answer:

Inessa05 [86]3 years ago

3 0

So the problem is $256=x^4$ and you need to find x.

You can find x by taking fourth root of 256. The easiest way is to use your calculator. On my scientific calculator, it is 2nd then the button ^ that is $\sqrt[x]{}$
You get the answer of 4.

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0.34 x ? =3.4 what is the value of the missing number

Yakvenalex [24]

Answer:

the answer is 10

Step-by-step explanation:

0.34 x 10 =3.4

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2 years ago

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Factor x^4 + x y^3 + x^3 + y^3 completely. Show your work.

andrey2020 [161]

$\bf x^4+xy^3+x^3+y^3\impliedby \textit{now let's do some grouping}
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\\\\\\
\stackrel{\stackrel{common}{factor}}{(x^3+y^3)}(x+1)\\\\
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\textit{now recall that }\qquad \qquad \textit{difference of cubes}
\\ \quad \\
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(x+y)(x^2-xy+y^2)(x+1)$

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3 years ago

The following graph represents the distance a commercial airplane travels over time, at cruising speed and an altitude of 35,000

ANEK [815]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the time in hours

y ----> the distance in miles

<em>Find the value of k</em>

For the point (4,2268)

$k=\frac{2,268}{4}=567\ mph$

The slope represent the speed of the airplane

so

The linear equation is

$y=567x$

Part 1 :

The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.

Part 2 :

The point (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours

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3 years ago

Match each fraction with the equivalent fraction on the right

Nikolay [14]

Answer:

3/4 - 6/8

1/3 - 2/6

1/2 - 5/10

3/5 - 6/10

1/4 - 2/8

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2 years ago

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The coldest temperature in New York City was -15 on February 9th 1934, The next day the temperature rose 42 degrees. Write an ex

masya89 [10]

Answer:

27°C

Step-by-step explanation:

The temperature on February 9th 1934 = -15°C

The next day the temperature rose 42 degrees.

We need to find an expression for the temperature on February 10th.

February 10th temperature = -15 + 42

= 27°C

So, the temperature on February 10th is 27°C.

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2 years ago