Answer:
The time rate of change of flux is
Explanation:
Given :
Current A
Area of plate
Plate separation m
(A)
First find the capacitance of capacitor,
Where
F
But
Where
Now differentiate above equation wrt. time,
Therefore, the time rate of change of flux is
Well since it is an upward force.. its b or c.. I think its b..
The author's best argument against the light-rail project is that it is unnecessary. A combination of trams characterizes light rail transit, a type of passengers urban rail transportation.
<h3>What does light rail accomplish?</h3>
In big cities, LRT can function as an independent organization or as a complement to heavy rail and passenger rail systems. The fastest and most economical interurban transport in a city is provided by LRT.
<h3>What does light rail accomplish?</h3>
Heavy rail systems can be supplemented by LRT, and commuter rail networks in big cities can function independently. In a metropolitan area, LRT offers the fastest and most affordable interurban transportation service. It is intended to close a considerable gap between light rail and local buses.
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Answer:
Explanation:
There are a couple of assumptions I had to make here and also a couple of rules based on what I use in my classroom when I teach the Law of Momentum Conservation. First of all, I am going to call the 8kg ball 1 and say that it is moving to the right (and right is positive), and that means that the 3kg ball is ball 2 and say that it is moving to the left (and left is negative). I had to assume that the 2 balls were moving towards each other; hence, the different signs assigned to their movement. I also added in another significant digit since we have only 1 in most of these values and adding in a .0 is not going to change the value of any number. The Law of Momentum Conservation in this particular instance says
which is the mathematical way of saying that the momentum after the collision is the same as the momentum before it. Filling in:
and doing the math here simplifies to
32 - 42 = -16 + 3.0v and
-10 = -16 + 3.0v and
6.0 = 3.0v so
v = 2.0 (and the positive indicates that ball 2 is now moving to the right)
To develop this problem it is necessary to apply the concepts related to the angular resolution of a telescope as well as to the arc length.
The arc length can be defined as
Where
r= Radius
\theta = Angle
At the same time the angular resolution of a body is given under the proportion
Where
= Wavelength
D = Diameter
Our values are given as
Then the angle of separation of the two objects seen from the observer is of
Finally, using the proportion of the arc length, in which we have the radius and angle we can know the separation of the two objects by: