Answer:
Centripetal acceleration
Explanation:
Centripetal force tends to keep an object moving within a circular or curved path to maintain its course while centripetal acceleration is what tends to accelerate the object towards the centre of the curve or circle
Answer:
Kinetic energy of diver at 90% of the distance to the water is 9000 J
Explanation:
Let d is the distance between the position of the diver and surface of the pool.
Initially, the diver is at rest and only have potential energy which is equal to 10000 J.
As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.
Energy before diving = Energy during diving
(Potential Energy + Kinetic Energy) = (Kinetic Energy + Potential Energy)
When the diver reaches 90% of the distance to the water, its kinetic energy
is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,
K.E. =
K.E. = 9000 J
Answer:
Energy gained by the second particle = 12Uo
Explanation:
Given Data;
Resistant force = 12F
Initial kinetic energy = Uo
Calculating the kinetic energy gained, we have;
u = f *r
where f= resistant force = 20F
r = initial kinetic energy = Uo
Therefore,
U = 12 * uo
= 12 Uo
Therefore, energy gained by the second particle = 12Uo
KE= 0.5(m)(v^2)
KE= 250,000 J
Answer:
First Car Avg: Velocity=0.11 m/s
Second Car Avg: Velocity=0.28 m/s
Explanation:
Data
D1 (First Car Displacement)=0.25m
T1 (First Car total time taken)=2.23s
D2 (Second Car Displacement)=0.25m
T2(Second Car time taken)=3.13-2.23=0.9s
Avg: Velocity1=?
Avg: Velocity2=?
Solution
Avg: Velocity1=D1/T1
Avg: Velocity1=0.25/2.23
Avg: Velocity1=0.11 m/s
Avg: Velocity2=D2/T2
Avg: Velocity2=0.25/0.9
Avg: Velocity2=0.28 m/s