Determining the identity of substances is a critical part of chemistry because once the substance's identity is known, we can predict its behavior and understand the scenarios that it is involved in better.
For example, consider an industrial pipe where fouling (scaling) is occurring. If the compounds present in the scales are identified, steps may be taken to prevent and remove the scaling. This is one of many examples where identifying chemical substances is of high importance.
No that’s is the electronic configuration for fluorine.
<span>The rate of infusion is 2.1L/19h or 2100mL/19h (as 1L = 100 mL).
To convert 19 hours to minutes we multiply as follows:
19 hours = (19 hours) x (60 minutes/1 hour) = 1140 minutes
So the rate of infusion becomes:
2100mL /1140 min
In order to converted mL to drops (gtt) we multiply the rate of infusion with the drop factor to get the drip rate:
(2100mL/1140min) x (20 gtt/mL) = 36.8 gtt/min</span>
Answer:
D.
Explanation:
You try to get 8 electron on the outermost "shell" so you have no left over or "valence" electrons.
Answer:1. ![Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=Rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. The rate constant (k) for the reaction is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![rate=k[CHCl_3]^x[Cl_2]^y](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5Ex%5BCl_2%5D%5Ey)
k= rate constant
x = order with respect to 
y = order with respect to 
n = x+y= Total order
1. a) From trial 1: ![0.0035=k[0.010]^x[0.010]^y](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5Ex%5B0.010%5D%5Ey)
(1)
From trial 2: ![0.0069=k[0.020]^x[0.010]^y](https://tex.z-dn.net/?f=0.0069%3Dk%5B0.020%5D%5Ex%5B0.010%5D%5Ey)
(2)
Dividing 2 by 1 :![\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0069%7D%7B0.035%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D%7Bk%5B0.010%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore x=1.
b) From trial 2: (3)
From trial 3: ![0.0098=k[0.020]^x[0.020]^y](https://tex.z-dn.net/?f=0.0098%3Dk%5B0.020%5D%5Ex%5B0.020%5D%5Ey)
(4)
Dividing 4 by 3:![\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0098%7D%7B0.0069%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.020%5D%5Ey%7D%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore 
![rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. to find rate constant using trial 1:
![0.0035=k[0.010]^1[0.010]^\frac{1}{2}](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5E1%5B0.010%5D%5E%5Cfrac%7B1%7D%7B2%7D)
