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Serjik [45]
3 years ago
8

What is the purpose of attaching the clip/ clamp with graphite of the the pencil to the battery?

Chemistry
1 answer:
Sonja [21]3 years ago
4 0
The pencil attached to the negative terminal of the battery collects hydrogen gas while the one connected to the positive terminal collects oxygen.
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A sealed helium balloon with an internal pressure of 1.00 atm and a volume of 4.50 L at 293 K is moved. What volume will the bal
bixtya [17]

Answer:

6.48 L

Explanation:

From the question,

Applying

PV/T = P'V'/T'......................... Equation 1

P = initial pressure of the helium balloon, V =  Initial volume of the balloon, T = Initial temperature of the balloon, P' = Final pressure of the balloon, T' = Final temperature of the balloon, V' = Final volume of the balloon.

make V' the subject of the equation

V' = PVT'/P'T......................... Equation 2

Given: P = 1 atm, V = 4.5 L, T' = 253 K, T= 293 K, P' = 0.6 atm

Substitute these values into equation 2

V' = (4.5×1×253)/(0.6×293)

V' = 1138.5/175.8

V' = 6.48 L

8 0
3 years ago
When glucose is fermented, ethanol is formed together with ………………….
levacccp [35]

Answer:

carbon dioxide and oxygen

3 0
3 years ago
How many carbon atoms are represented by the model below? <br>A. 12 <br>B. 5 <br>C. 4 <br>D. 6 ​
solong [7]

Answer:

D. 6

Explanation:

Each pointy end represents 1 carbon. So in total we have six carbons.

The name of this organic compound is hexane.

4 0
3 years ago
Read 2 more answers
60 grams of ice will require _____ calories to raise the temperature 1°C.
guajiro [1.7K]

Answer:

60 grams of ice will require 30.26 calories to raise the temperature 1°C.

Explanation:

The amount of heat (Q) to raise the temperature of 60.0 g of ice by 1°C can be calculated from:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released or absorbed by the system.

m is the mass of the ice (m = 60.0 g).

c is the specific heat capacity of ice (c = 2.108 J/g.°C).

ΔT is the temperature difference (ΔT = 1.0 °C).

∴ Q = m.c.ΔT = (60.0 g)(2.108 J/g.°C)(1.0 °C) = 126.48 J.

<em>It is known that 1.0 cal = 4.18 J.</em>

<em>∴ Q = (126.48 J)(1.0 cal / 4.18 J) = 30.26 cal.</em>

7 0
3 years ago
Two identical metal spheres at 8 °C are put into two beakers with equal amounts of water, as shown below.
leva [86]

Answer:

Correct answer is B.

Explanation:

Took the test and got this right. :)

7 0
3 years ago
Read 2 more answers
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