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3 years ago

How many atoms are there in 32.45 grams of Magnesium?

Chemistry

1 answer:

levacccp [35]3 years ago

5 0

Answer:

8.13 ×10²³ atoms

Explanation:

Given data:

Mass of magnesium = 32.45 g

Number of atoms = ?

Solution:

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 32.45 g/ 24 g/mol

Number of moles = 1.35 mol

Number of atoms:

1 mole contain 6.022×10²³ atoms

1.35 mol × 6.022×10²³ atoms/ 1mol

8.13 ×10²³ atoms

You might be interested in

How many grams of aluminum chloride are produced when 5.96 grams of aluminum are reacted with excess chlorine gas? Start with a

Vadim26 [7]

Answer:

29.47 g of AlCl₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Al + 3Cl₂ —> 2AlCl₃

Next, we shall determine the mass of Al that reacted and the mass of AlCl₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 2 × 27 = 54 g

Molar mass of AlCl₃ = 27 + (35.5× 3)

= 27 + 106.5

= 133.5 g/mol

Mass of AlCl₃ from the balanced equation = 2 × 133.5 = 267 g

SUMMARY:

From the balanced equation above,

54 g of Al reacted to produce 267 g of AlCl₃.

Finally, we shall determine the mass of AlCl₃ produced by the reaction of 5.96 g of Al. This can be obtained as follow:

From the balanced equation above,

54 g of Al reacted to produce 267 g of AlCl₃.

Therefore, 5.96 g of Al will react to produce = (5.96 × 267)/54 = 29.47 g of AlCl₃.

Thus, 29.47 g of AlCl₃ were obtained from the reaction.

3 0

2 years ago

An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the

san4es73 [151]

Answer:

the ionic radius of the anion $r^- = 312.52 \ pm$

Explanation:

From the diagram shown below :

The anion $Cl^-$ is located at the corners

The cation $Cs^+$ is located at the body center

The Body diagonal length = $\sqrt{3 \ a }$

∴ $2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a} \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a$

Given that :

$\frac{r^+}{r^-} =0.84$ (i.e the ratio of the ionic radius of the cation to the ionic radius of

the anion )

$0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a \\ \\ 1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a$

Also ; a = 664 pm

Then :

$r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm$

Therefore, the ionic radius of the anion $r^- = 312.52 \ pm$

4 0

3 years ago

What is osmotic pressure of a solution that contains 13.7 g of propyl alcohol (C3H7OH) dissolved in enough water to make 500 mL

azamat

Answer:

Π = iMRT ½

Explanation:

111 g

= 0.033 mol

0.033 mol CaCl2

0.09632 kg solvent

= 0.0344 m

13.7 g x 1 mol C3H7OH

60.10 g

0.5 L

(0.0821 L.atm/K.mol) (300.15K

4 0

3 years ago

If a 600 gram radioactive sample goes through 3 half-lives, how would be left?

olga_2 [115]

Answer:

75 g

Explanation:

1 half life = 600/2 = 300g

2 half life = 300/2 = 150g

3 half life = 150/2 = 75g

5 0

2 years ago

A sample of monochloro pentaborane (9), b5h8cl, has a mass of 20.1 g. what amount, in moles, does this mass represent?

dolphi86 [110]

The number of moles in monochloro pentaborane (9) $B_5H_8Cl$ is 0.37056.

We know that ,

Number of moles = Given mass/ Molar mass

Given mass of monochloro pentaborane (9) is 20.1 g

The molar mass of monochloro pentaborane (9) is

= $5*B + 8*H + Cl$

= $5* 10.811 + 8 * 1 + 35.453$

= 54.241

Thus number of moles = 20.1/54.241

= 0.37056

To know more about mole concept

brainly.com/question/20483253

#SPJ4

5 0

2 years ago