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Maru [420]
3 years ago
13

Which kind of substance accepts an electron pair?

Chemistry
2 answers:
sp2606 [1]3 years ago
8 0
The substance that accepts electron-pairs is acids. Bases accept protons.
Hope this helps you like it did me :)
Anastaziya [24]3 years ago
5 0

Answer : The correct option is Acid.

Explanation :

  • Acid : Acids are those which accepts an electron-pairs.
  • Base : Bases are those which donates ab electron-pairs.
  • Alkali : It is a base that dissolves in water. It is basically a base and the pH greater than 7.
  • Hydroxide ion : It is a poly-atomic ion which is negatively charged.

Therefore, the acid is a substance which accepts an electron-pair.

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Qual é a etapa onde ocorre a adição de cloro para eliminação de microorganismos patogênicos? AULA DE CIÊNCIAS 6° ano
-BARSIC- [3]

Answer:

A desinfecção

Explanation:

A desinfecção é o processo no qual o cloro é adicionado para matar microorganismos patogênicos prejudiciais, como bactérias, vírus, etc. Este é um processo químico e biológico. alguns desinfetantes comuns são cloro, dióxido de cloro e ozônio.

6 0
3 years ago
A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o
Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where \frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}

We're only talking about molar mass and time (t) here so we'll just concentrate on \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}. Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2

{\frac{M2}{131} } = (0.47)^2

{\frac{M2}{131} } = 0.22

M2= 0.22 x 131

M2= 28.93 g/mol

8 0
3 years ago
What is the application of Complexometric titration? ​
PtichkaEL [24]

Explanation:

Complexometric titration (sometimes chelatometry) is a form of volumetric analysis in which the formation of a colored complex is used to indicate the end point of a titration. Complexometric titrations are particularly useful for the determination of a mixture of different metal ions in solution.

hope it will help u ✌️

7 0
3 years ago
In this part of the periodic table, what type of elements are in the group that includes elements c, o, and s?
wolverine [178]
Metalsnonmetalssemimetals
5 0
3 years ago
5. Which of the following is a synthesis reaction? (2 points)
gulaghasi [49]
2H2 + O2 = 2H2O since two elements created a compound, in this case water.
8 0
3 years ago
Read 2 more answers
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