The concentration of propionate ions at equivalent point is 0. 084 M
calculation
write the equation for reaction
HC3H5O2 + KOH → H2O + KC3H5O2
find the moles of KOH used
moles= molarity × volume in liters
volume in liters = 37.48 ml/1000 =0.03718L
molarity = 0.141 M
moles is therefore = 0.141 M x0.03718 = 5.24238 x10^-3 moles
by use of mole ratio between KOH and K3C3H5O2 which is 1:1 the moles of K3C3H5O2 is also = 5.24238 x10^-3 moles
molarity is therefore = number of moles/volume in liters
volume in liters = 25/1000 +37.48/1000=0.06248 L
molarity of propionate ions is therefore = (5.24238 x10^-3) / 0.06248 = 0.084 M
<span>a. If the actual mass of Magnesium used was larger then the measured and the amount of gas produced should be greater
b. when gas was cooler than its surroundings its density would be
greater and the volume would appear to be smaller. This is because the gas molecules are very active and when heated they will expand.
</span>so they both bound increase the calculated moles of gas collected in the experiment
A substance above its critical pressure is <span>supercritical.
I hope this helps you! Good luck :)</span>
