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Fudgin [204]
2 years ago
7

Joshua is trying to decide if there is a relationship between a driver's age and the number of traffic tickets they get he surve

ys 150 people in three towns and recorded their age how many tickets they got in the last year in the town they live in he creates a graph of his data what is the independent variable
Mathematics
1 answer:
Rashid [163]2 years ago
4 0

Hello!


The number of tickets is dependent on age, so age is the independent variable.


Think of it as a y = mx equation. In this equation, x is the input, and y changes depending on the value of x inputted.


In this situation, y is the number of tickets, as y changes depending on the age x inputted. x is age, the independent variable.




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bagirrra123 [75]

Answer:

a) If c=3662 then q=228 and r=14.

b) If c=-3662, then q=-229 and r=2

Step-by-step explanation:

a) Observe that 229*16=3664, since r must be in the interval [0,16), then 229 doesn't work, but 228*16=3648 and 3662-3648=14.

Then 3662=228*16+14.

b) Observe that -228*16=-3648 and -3648-14=-3662, but r= must be positive. Then -228 doesn't work.

But observe that -229*16=-3664 and -3664+2=-3662. So -3662=-229*16+2

4 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

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then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
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Answer:

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Step-by-step explanation:

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