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PSYCHO15rus [73]
3 years ago
15

A special deck of cards has 5 red cards, and 4 purple cards. The red cards are numbered 1, 2, 3, 4, and 5. The purple cards are

numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card. R = card drawn is red E = card drawn is even-numbered a. How many elements are there in the sample space? b. P(E) = Round your answer to two decimal places.
Mathematics
1 answer:
True [87]3 years ago
4 0

Answer:

a. 9

b. 4/9 or 0.444

Step-by-step explanation:

R=red card={R1,R2,R3,R4,R5}

E=even card={R2,R4,P2,P4}

n(R)=5

n(E)=4

a.

There 5 red and 4 purple card so, the sample space would be

Sample space=S={R1,R2,R3,R4,R5,P1,P2,P3,P4}

number of elements in sample space=n(S)=9

So, the number of elements in the sample space are 9.

b.

P(E)=n(E)/n(S)

P(E)=4/9 or 0.444

Thus, the probability of an even numbered card is 0.444.

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Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be x.

So, 54 is equivalent to 36.

Thus, 17 is equivalent to x.

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Dividing both sides by 54 we get:

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Thus, the width of sign = 11.33 inches.

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