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PSYCHO15rus [73]
3 years ago
15

A special deck of cards has 5 red cards, and 4 purple cards. The red cards are numbered 1, 2, 3, 4, and 5. The purple cards are

numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card. R = card drawn is red E = card drawn is even-numbered a. How many elements are there in the sample space? b. P(E) = Round your answer to two decimal places.
Mathematics
1 answer:
True [87]3 years ago
4 0

Answer:

a. 9

b. 4/9 or 0.444

Step-by-step explanation:

R=red card={R1,R2,R3,R4,R5}

E=even card={R2,R4,P2,P4}

n(R)=5

n(E)=4

a.

There 5 red and 4 purple card so, the sample space would be

Sample space=S={R1,R2,R3,R4,R5,P1,P2,P3,P4}

number of elements in sample space=n(S)=9

So, the number of elements in the sample space are 9.

b.

P(E)=n(E)/n(S)

P(E)=4/9 or 0.444

Thus, the probability of an even numbered card is 0.444.

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Answer:

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Step-by-step explanation:

This will be solved by the formula:

FV=I(1+r)^t

Where

FV is the future value (what we are looking for)

I is the initial amount (which is $1000)

r is the rate of interest per period (8% is annual interest, but the period is SEMI-ANNUAL, that's 6 months, half of yearly. So r would be half of 8%, which is 4% or r = 0.04)

t is the times compounding occurs in the whole time (The whole time period is 5 years, but compounding occurs semi-annually, so 5*2 = 10 times. Thus, t = 10)

<em>plugging the info into the formula we will get our answer.</em>

<em>FV=I(1+r)^t\\FV=1000(1+0.04)^{10}\\FV=1000(1.04)^{10}\\FV=1480.24</em>

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3 years ago
Two factors of -48 have a difference of 19 the factor with the greater absolute value is positive what is the sum of the factors
MA_775_DIABLO [31]
1). Two factors of -48 => x * y = -48

=> the absolute values of the two numbers may be:

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2). Have a differencie of 19 = > x - y = 19


That makes that the numbers  be + 16 and - 3


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Answer:

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Step-by-step explanation:

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