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PSYCHO15rus [73]
3 years ago
15

A special deck of cards has 5 red cards, and 4 purple cards. The red cards are numbered 1, 2, 3, 4, and 5. The purple cards are

numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card. R = card drawn is red E = card drawn is even-numbered a. How many elements are there in the sample space? b. P(E) = Round your answer to two decimal places.
Mathematics
1 answer:
True [87]3 years ago
4 0

Answer:

a. 9

b. 4/9 or 0.444

Step-by-step explanation:

R=red card={R1,R2,R3,R4,R5}

E=even card={R2,R4,P2,P4}

n(R)=5

n(E)=4

a.

There 5 red and 4 purple card so, the sample space would be

Sample space=S={R1,R2,R3,R4,R5,P1,P2,P3,P4}

number of elements in sample space=n(S)=9

So, the number of elements in the sample space are 9.

b.

P(E)=n(E)/n(S)

P(E)=4/9 or 0.444

Thus, the probability of an even numbered card is 0.444.

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Answer:

i don't speak spanish bro sorry

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2 years ago
the area of a rectangular patio is represented by the expression 6x^2+13-5. the width of the patio is (3x-1) write an expression
jok3333 [9.3K]

<span>I think you meant 6x²+13x-5 so first thing we have to do is factor it which is really quite tricky with this kind of trinomial so first take ac which is 6 times -5 so -30 now figure out factors of -30 that will add up to 13 how about 15 and -2 now that we have the factors write the equation again</span>

<span /><span> 6x²+15x-2x-5  </span>split the equation in half<span />

<span>6x²+15x   -2x-5 so out of the first equation we can pull a 3x out</span>

<span>3x(2x+5) and out of the second we can pull a negative 1</span>

<span>3x(2x+5) -1(2x+5) rewrite it</span>

<span>(3x-1)(2x+5) so the 3x-1 is the factor we already had so the other side is (2x+5)</span>

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6 0
3 years ago
HELP ME PLEASE!!
LUCKY_DIMON [66]

Using a system of equation, we have that:

a)

  • x, which is the cost of on-site service.
  • y, which is the cost of at-store service.
  • z, which is the cost of by-mail service.

b)

The system is:

x = 3y

z = y - 10

15x + 40y + 5z = 3100

c)

The cost of one on-site repair service is of $90.

Item a:

The variables are:

  • x, which is the cost of on-site service.
  • y, which is the cost of at-store service.
  • z, which is the cost of by-mail service.

Item b:

On-site service costs <u>3 times as much as at-store service</u>, thus:

x = 3y

By mail service costs <u>$10 less than at-store</u>  service, thus:

z = y - 10

Last week, the shop completed <u>15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100</u>, thus:

15x + 40y + 5z = 3100

The system is:

x = 3y

z = y - 10

15x + 40y + 5z = 3100

Item c:

  • The cost of one on-site repair service is x.
  • First, replacing the first two equations into the third, we find y, and then with it we find x.

15x + 40y + 5z = 3100

15(4y) + 40y + 5(y - 10) = 3100

60y + 40y + 5y = 3150

105y = 3150

y = \frac{3150}{105}

y = 30

Then

x = 3y = 3(30) = 90

The cost of one on-site repair service is of $90.

A similar problem is given at brainly.com/question/24823220

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Answer:

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Step-by-step explanation:

Given the point (- 3, - 5)

where x = - 3 is the input and y = - 5 is the output

The function can be represented by

y = f(x), that is

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5 packs of stamps and 7 packs of envelopes. There will be a total of 70 envelopes and stamps.
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