20 POINTS!!!!!!!! What is the equation of this line in Slope-Intercept Form?

Mathematics

2 answers:

Bumek [7]3 years ago

8 0

where m is the slope of the line and b is the y-intercept of the line, or the y-coordinate of the point at which the line crosses the y-axis. To write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope.

spin [16.1K]3 years ago

3 0

The equation is y = -3/4x + 4. Because the y-intercept found here is 4, and to get to another point on the line you need to go down on the y-axis 3, -3, and go over to the right of the graph on the x-axis 4.

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What is the value of this expression when a = 4, b = -5, and c = -7?

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The value of the given expression is -878.08.

Step-by-step explanation:

Here, the given question is INCOMPLETE.

The complete question is:

Evaluate the expression for a = 4, b = -5, and c = -7. $4a^2b^{-2}c^3$

Here, substitute the vale of a = 4, b = -5 and c = -7, we get:

$4a^2b^{-2}c^3 = (\frac{4a^2c^3}{b^2}) = (\frac{4(4)^2(-7)^3}{(-5)^2})\\= (\frac{64 \times 343}{25}) =\frac{21,952}{25} = 878.08\\\implies 4a^2b^{-2}c^3 = 878.08 ( a = 4, b = -5 ,c = -7)$