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BARSIC [14]
3 years ago
10

Solve for x: (5 points) negative 3 over 2, multiplied by x minus 9 equals negative 27 a −24 b −12 c 11 d 12

Mathematics
1 answer:
umka21 [38]3 years ago
4 0

Answer: b, 12

explanation: combine -3/2 * x and u get -3/2x. then isolate the variable by doing the inverse of subtraction on both sides. (add 9 on both sides). then do the inverse of multiplication on both sides. (divide by -3/2 on both sides)

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Write an equation for the inverse:<br> f(x) = x-10/5
Hatshy [7]

Answer:

5x+10

Step-by-step explanation:

let f(x)=(x-10)/5=y

now write 'x' in term of y

i.e, x-10=5y

i.e, x=5y+10

now replace y with x to get required inverse of f(x)

=5x+10

8 0
3 years ago
Andrea reads 36 pages each night. How many pages does Andrea read in 42 nights?
ioda

Answer:

1,512

Step-by-step explanation:

36x42

6 0
3 years ago
Solve for x in the equation x2 +11x+121/4=125/4
aksik [14]

Answer:

x= −11 2 + 5 2 √5 or x= −11 2 + −5 2 5

Step-by-step explanation:

4 0
3 years ago
HELP! PLZ I NEED THIS ASAP
harina [27]

Answer:

2x^{4}+x^{3}-x+2

Step-by-step explanation:

To find which one is prime, let's try to factor them all. We can use the factoring by grouping method.

x^{3}+3x^{2}-2x-6

x^{3}+3x^{2}and-2x-6

x^{2}(x+3)and-2(x+3)

So this one is not prime, since you can still factor it.

x^{3}+2x^{2}-3x-6

x^{3}+2x^{2}and-3x-6

x^{2}(x-2)and3(x-2)

So this one is not prime, since you can still factor it.

4x^{4}+4x^{2}-2x-2

4x^{4}+4x^{2}and-2x-2

4x^{3}(x+1)and-2(x+1)

So this one is not prime, since you can still factor it.

2x^{4}+x^{3}-x+2

2x^{4}+x^{3}and-x+2

x^{3}(2x+1)and -x+2 cannot be further factored.

Therefore, 2x^{4}+x^{3}-x+2 is a prime.

6 0
4 years ago
Please help this is important
deff fn [24]

Answer:

below

Step-by-step explanation:

You've been asked to use specific x-values. Simply replace the x in the equation for each of your x-values then graph.

first equation!!

(x,y)

y=-2x+5

x-value: -2

y=-2(-2)+5

y=4+5

y=9

(-2, 9)

x-value: -1

y=-2(-1)+5

y=2+5

y=7

(-1, 7)

x-value: 0

y=-2(0)+5

y=0+5

(0, 5)

x-value: 1

y=-2(1)+5

y=-2+5

y=3

(1, 3)

x-value: 2

y=-2(2)+5

y=-4+5

y=1

(2, 1)

second equation :)

(x,y)

y=x^2 +2

x-value: -2

y=-2^2 +2

y=4+2

y=6

(-2, 6)

x-value: -1

y=-1^2 +2

y=1+2

y=3

(-1, 3)

x-value: 0

y=0^2 +2

y=0+2

(0, 2)

x-value: 1

y=1^2 +2

y=1+2

y=3

(1, 3)

x-value: 2

y=2^2 +2

y=4+2

y=6

(2, 6)

third equation

(x,y)

y=√2 x+1

x-value: 1

y=√2 1+1

y=1+1

y=2

(1, 2)

x-value: 4

y=√2 4+1

y=2+1

y=3

(4, 3)

x-value: 9

y=√2 9+1

y=3+1

y=4

(9, 4)

x-value: 16

y=√2 16+1

y=4+1

y=5

(16, 5)

x-value: 25

y=√2 25+1

y=5+1

y=6

(25, 6)

fourth (last) equation :-)

(x,y)

y=4/x

x-value: -4

y=4/-4

y=-1

(-4, -1)

x-value: -2

y=4/-2

y=-2

(-2, -2)

x-value: -1

y=4/-1

y=-4

(-1, -4)

x-value: 0

y=4/0

y=0

(0, 0)

x-value: 1

y=4/1

y=4

(1, 4)

x-value: 2

y=4/2

y=2

(2, 2)

x-value: 4

y=4/4

y=1

(4, 1)

5 0
3 years ago
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