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stiv31 [10]
3 years ago
6

Rita promises to give her 12–year–old daughter $12,000 when she turns 18. How much does she need to put in the bank now if the i

nterest rate is 12 percent per year?
$6,079.58



$5,248.19



$6,502.12
Mathematics
1 answer:
grigory [225]3 years ago
4 0
<span>she needs to put $6,079.58 in the bank now</span>
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All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessarily the same as the weigh
BaLLatris [955]

Answer:

The largest possible weight of flour is 11.25  pounds.

Step-by-step explanation:

To start with, we will assume that the weight of 1 sack of sugar = x pounds

We will also assume that the weight of 1 sack of flour = y pounds

So, the weight of 2 sacks of sugar = 2 * (x) = 2x

Same thing goes for the weight of 3 sacks of flour  = 3 * (y) = 3y

Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds

= 2x + 3y ≤ 40............ we'll call that equation 1.

Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds

= y ≤ 2x + 5........................ we'll call that equation 2

Therefore, we'll solve for the values of x and y in the two equations and we will get:

2x + 3y ≤ 40

y ≤  2x + 5

Now, substitute the value of y into equation 1

2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40

⇒ 2x + 6x + 15= 40

⇒ 8x + 15 = 40

⇒ 8x = 25

⇒ x = 25/8

⇒ x = 3.12

x cannot be more than 3.12 pounds, so we solve for y

Putting the value of x into equation 2, we'll get

⇒ 2y + 5 = 2(3.12) + 5

⇒ y = 11.25 pounds.

So, n cannot be more than 11.25 pounds

8 0
2 years ago
The postal service charges $2 to ship packages up to 5 ounces in weight and $0.20 for each additional ounce up to 20 ounces. Aft
Luda [366]

Answer:

The domain is all of the x values. From the graph, all of the x values are greater than or equal to 0 so the answer is x ≥ 0.

3 0
3 years ago
What is the GCF of 81, 252, and 567?
Leto [7]

It's 9. Take 81/9 and that equals nine

7 0
3 years ago
uppose that we have a function with a constant amount of work done in initialization, a call to a log-linearsorting algorithm, a
White raven [17]

Answer:

The running time is quadratic (O(n²) )

Step-by-step explanation:

For the set up, we have a constant running time of C. The, a log-linearsorting is called, thus, its execution time, denoted by T(n),  is O(n*log(n)). Then, we call n times a linear iteration, with a running time of an+b, for certain constants a and b, thus, the running time of the algorithm is

C + T(n) + n*(a*n+b) = an²+bn + T + C

Since T(n) is O(n*log(n)) and n² is asymptotically bigger than n*log(n), then the running time of the algorith is quadratic, therefore, it is O(n²).

7 0
2 years ago
A piece of string is 325 centimeters long. You need the string to be 114 meters long. How many centimeters should you cut off?
sertanlavr [38]

There are 100 centimeters in 1 meter.1 and 1/4 meters can also be written as 1.25, since 1/4 = 0.25.To find the answer, convert 1.25 meters to centimeters.
1 meter = 100 centimeters1.25 meters = x centimeters1.25 is 125% of 1. In other words, there is a 25% increase.
Now apply this increase to the centimeters side.125% = 1.251.25 • 100 = 125
So 1.25 meters (1 and 1/4 meters) equals 125 centimeters.
The string is 325 centimeters.In order for the string to be 125 centimeters, you need to cut some off.To find how much you need to cut off, subtract 125 from 325.325 - 125 = 200
Answer: In order for your string to be 1 and 1/4 meters, you must cut 200 centimeters off the original 325 centimeter long string.
5 0
2 years ago
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