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2 years ago

Please help!!! Composition of functions~

Mathematics

1 answer:

Ber [7]2 years ago

7 0

Answer:

$g(h(-8)) = 119$

Hence, option B) is true.

Step-by-step explanation:

Given

g(x) = 2x-5

h(x) = x² - 2

To determine

$g(h(-8)) = ?$

In order to determine g(h(-8)), first we need to determine h(-8), so

substituting x = -8 in h(x) = x² - 2

h(x) = x² - 2

h(-8) = (-8)² - 2

h(-8) = 64 - 2

h(-8) = 62

so we can write

$g(h(-8)) = g(62)$

now, to determine g(62), substitute x = 62 in g(x) = 2x-5v

g(x) = 2x-5

g(62) = 2(62) - 5

g(62) = 124 - 5

g(62) = 119

so,

$g(h(-8)) = g(62)=119$

Therefore,

$g(h(-8)) = 119$

Hence, option B) is true.

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Mandarinka [93]

Answer:

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Parallel lines have the same slope, so the line will also have a slope of 1.

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3 years ago

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Alekssandra [29.7K]

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1. A. $33 loss

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Step-by-step explanation:

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2 years ago

What is the area of the rectangle?<br><br> [1] un2

mezya [45]

(-2,3) to (2,-3)

6^2 + 4^2 = c^2

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————

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————

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3 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is