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igor_vitrenko [27]

3 years ago

13

The first floor of Marcus’ house is 1,440 square feet. He will cover 1,033 square feet with wood and the rest with tile. A box o

f tiles will cover 11 square feet.
How many boxes of tile does Marcus need to buy to cover the floor?

1 answer:

notsponge [240]3 years ago

5 0

37 boxes of tiles,because you minus 1440-1033=407 thenyou keep adding in eleven and i got 11*37=407 so thats your answer 37.

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I need help with this questions

SSSSS [86.1K]

Answer:

<u>Picture 1</u>

Your choice C is correct

(x - (-2))² + (y - 9)² = 5² ⇒
(x + 2)² + (y - 9)² = 25

<u>Picture 2</u>

(x + 5)² + (y - 6)² = 36
(x - (-5))² + (y - 6)² = 6²
r = 6, (h, k) = (-5, 6)

Correct choice is C

<u>Picture 3</u>

(x + 5)² + (y + 2)² = 81
(x - (-5))² + (y - (-2))² = 9²
r = 9, (h, k) = (-5, -2)

Correct choice is C

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3 years ago

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Alona [7]

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3 years ago

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erik [133]

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3 years ago

Sasha and Mona practiced swimming every day. They increased the number of minutes of swimming every week as described below:

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4 0

3 years ago

Read 2 more answers

The question is in the screenshot

Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < $\pi$ /2 => tan x > 0

As 0< y < $\pi$ /2 => tan y > 0

We have the formula:

$\frac{1}{sin^{2}x } =1 + cot^{2}x$ => $\frac{1}{(8/17)^{2} }$ = $1+cot^{2}x$ => $cot^{2} x=225/64$

As tan x = 1/(cotx) => $tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}$

As tan x > 0 => tan x = 8/15

$\frac{1}{cos^{2}y } = 1+tan^{2}y$ => $\frac{1}{(3/5)^{2} } = 1 + tan^{2} y$ => $tan^{2}y=\frac{16}{9}$

As tan y > 0 => tan y = 4/3

As tan (x-y)= $\frac{tan x - tan y}{1+ tanx * tany}$ $=\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}$

8 0

3 years ago