<span>a. 2 ft. 5 in. + 9 in.=2 ft 14 in.=2 ft. (12+2) in.=3 ft. 2 in. (since 1 ft.=12 in.);
</span>
<span> b. 4 yd. 8 in + 6 yd. 6 in. =(4+6) yd. (8+6) in.=10 yd. 14 in.=10 yd. (12+2) in.=10 yd. 1 ft. 2 in.;
</span>
<span>c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. + 13 yd. 1 ft. 3 in.=(29+55+13) yd. (2+1+1) ft. (11+10+3) in.=97 yd. 4 ft. 24 in.=97 yd. (3+1) ft. (12+12) in.=98 yd. 3 ft.=99 yd.
</span>
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in. + 7 sq. ft. 124 sq. in.=4,839 sq. yd. (8+7) sq. ft. (139+124) sq. in.=<span>4,839 sq. yd. 15 sq. ft. 263 sq. in. =</span>
<span>4,839 <span>sq. yd. 15 sq. ft. (144+119) sq. in.=</span></span><span>4,839 sq. yd. 16 sq. ft. 119 sq. in.=</span><span>4,839 <span>sq. yd. (9+7) sq. ft. 119 sq. in.=</span></span><span>4,840 <span>sq. yd. 7 sq. ft. 119 sq. in.</span></span>
R = kp/st
18 = 12k/(1/6 x 2)
18 = 12k/(1/3)
18 = 36k
k = 18/36 = 1/2
Answer:
6m + 2n
Step-by-step explanation:
we have to added up the like therms
like therms are therms that have the same literal part
6m + 2n
Answer:
Option D is correct.
VS = 20 units.
Step-by-step explanation:
The complete question is contained in the attached image to this answer.
From the image attached and the additional information about the triangles, it is evident that that triangle VSW is similar to triangle QSR.
Hence, we can write the ratio as
(VS/QS) = (VW/QR)
VS = 2a
QS = 2 × VS = 2 × 2a = 4a
VW = 2a - 2
QR = 3a + 6
(2a)/(4a) = (2a - 2)/(3a + 6)
Cross multiplying,
2a (3a + 6) = 4a (2a - 2)
3a + 6 = 2 (2a - 2)
3a + 6 = 4a - 4
4a - 3a = 6 + 4
a = 10
VS = 2a = 20 units.
Hope this Helps!!!
Answer:
<em>I've attached a picture of a unit circle with the quadrant labeled. </em>
<u>Calculate the degree of 5п 8 radians:</u>

<u>Locate the general location of 112.5° on the unit circle:</u>
It's between 120°(
) and 90°(
).
<u>Find the quadrant it lies in:</u>
Quadrant II