Answer:
here
Explanation:
Heterozygous male with type blood A has the genotype of IA IO. Heterozygous female with blood type B has the genotype of IB IO.
Crossing IA IO × IB IO;
25% IA IB - blood type AB
25% IA IO - blood type A
25% IB IO - blood type B
25% IO IO - blood type O
Answer:
C. 1/4
Explanation:
Let's assume that the allele for the spotted coat is "S" and the one for the even coat is "s". The allele "L" gives short horns while the recessive allele "l" imparts long horns. The genotype of the cattle heterozygous for both traits would be SsLl. A cross between two heterozygous cattle would produce progeny in following phenotype ratio=
9 spotted coat and short horns: 3 even coat and short horns: 3 spotted coat and long horns: 1 even coat and long horns.
Therefore, the proportion of the progeny with long horns = 4/16= 1/4
