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3 years ago

4/9 expressed as a percent please help and show work! Please

Mathematics

2 answers:

dusya [7]3 years ago

8 0

Thr the answer is 44% because if you round you will get 44%

coldgirl [10]3 years ago

7 0

4/9 as a percent is (about) 44% Work:
First get a decimal by dividing 4/9(4 divided by 9) you get 0.44 repeating
Next, take away the 0. and add a percent sign at the end of 0.44. You get 44%
Truly, the answer is 44.44444...% because the four repeats, but if you round it is simply 44%

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3 years ago

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3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

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Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$

$P(2>Z)=.97725$

We will use formula $P(a$ to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

$P(-1$

Upon converting 0.81859 to percentage we will get

$0.81859*100=81.859\approx 81.86$

Therefore, 81.86% of final exam score will be between 68 and 86.

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3 years ago

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3 years ago