Answer:
LENGTH= <em>1</em><em>6</em><em> </em><em>and</em><em> </em><em>WIDTH</em><em>=</em><em> </em><em>1</em><em>3</em>
Step-by-step explanation:
Let the length of rectangle be l
and, its width be b
So, according to question
l = b+3
and,
2(l+b)=58
[We know that perimeter of a rectangle= <em><u>2</u></em><em><u>(</u></em><em><u>l</u></em><em><u>+</u></em><em><u>b</u></em><em><u>)</u></em><em><u>]</u></em>
Substituting l=b+3 in 2nd equation
2(b+3+b)=58
2b+3=58/2
2b+3=29
2b=29-3=26
b=26/2
b= 13
So, l=b+3
l= 13+3=16
Hence the dimensions are 16 and 13
HOPE IT IS USEFUL