Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
If 1cm equals 1000 millimeters, then multiply 7 by 1000 and you will get your answer. 7 times 1000 equals 7,000 millimeters.
7*1000
Multiply
Final Answer: 7,000
Answer:
50 minutes = B
Step-by-step explanation:
Andre can run 5 miles in 40 minutes
for 1 miles = 40/5 = 8 minutes
1 mile = 1.61 kilometres
x = 10 kilometres
x= (10x1)/1.61= 10/1.61 = 6.21miles
- for 1 miles = 40/5 = 8 minutes
- 6.21 miles = 8 x 6.21 = 49.689 minutes ≈ 50 minutes = B
Answer:
Becky
Step-by-step explanation:
Look at it.... i mean 21:35 is the greatest in fraction, decimal and percentage.
Answer:
I believe its 66
Step-by-step explanation:
55×20%=11
55+11=66