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n200080 [17]
3 years ago
15

A 0.90- kg mass attached to a vertical spring of force constant 170 N/m oscillates with a maximum speed of 0.20 m/s . Find the f

ollowing quantities related to the motion of the mass.
Find the period.

Find the amplitude.

Find the maximum magnitude of the acceleration.
Express your answer using two significant figures.
Physics
1 answer:
Alex3 years ago
3 0

Explanation:

Given that,

The mass of the object, m = 0.9 kg

Force constant, k = 170 N/m

Maximum speed of the object, v = 0.2 m/s

Solution,

(a) The angular frequency of the object is given by :

\omega=\sqrt{\dfrac{k}{m}}

\omega=\sqrt{\dfrac{170}{0.9}}

\omega=13.74\ rad/s

The time period is given by :

T=\dfrac{2\pi}{\omega}

T=\dfrac{2\pi}{13.74}

T = 0.45 seconds

(b) The maximum velocity of the object in shm is given by :

v=A\omega

Amplitude,

A=\dfrac{v}{\omega}

A=\dfrac{0.2}{13.74}

A = 0.0145 m

(c) The maximum acceleration of the object is given by :

a=\omega^2A

a=(13.74)^2\times 0.0145

a=2.73\ m/s^2

Therefore, this is the required solution.

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A motorboat traveling with a current can go 160 km in 4 hours. against the current it takes 5 hours to go the same distance. Fin
MatroZZZ [7]
<h2>Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.</h2>

Explanation:

Let speed of motor boat be m and speed of current be c.

A motorboat traveling with a current can go 160 km in 4 hours.

   Distance = 160 km

   Time = 4 hours

    Speed = m + c

   We have

            Distance = Speed x Time

            160 = (m+c) x 4

            m + c = 40     --------------------- eqn 1

Against the current it takes 5 hours to go the same distance.

   Distance = 160 km

   Time = 5 hours

    Speed = m - c

   We have

            Distance = Speed x Time

            160 = (m-c) x 5

            m - c = 32     --------------------- eqn 2

eqn 1 + eqn 2

           2m = 40 + 32

             m = 36 km/hr

Substituting in eqn 1

               36 + c = 40

                      c = 4 km/hr

Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.

3 0
3 years ago
A 0.75 kg book is pushed across the table with an acceleration of 0.3 m/s2. What force is being applied to the
Brums [2.3K]

Answer:

\boxed {\boxed {\sf 0.225 \ Newtons}}

Explanation:

We are asked to find the force being applied to a book. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F= ma

The mass of the book is 0.75 kilograms and the acceleration is 0.3 meters per square second. Substitute these values into the formula.

  • m= 0.75 kg
  • a= 0.3 m/s²

F= 0.75 \ kg * 0.3 \ m/s^2

Multiply.

F =0.225 \ kg * m/s^2

1 kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 0.225 kilogram meters per second squared is equal to 0.225 Newtons.

F= 0.225  \ N

<u>0.225 Newtons of force</u> are applied to the book.

5 0
3 years ago
The temperature of a small metal cube is 75°c. A student places the cube into an insulated container of water at a temperature o
eduard
We can't tell without more information. We know it will be higher than 40 and lower than 75, but we don't know exactly where it will settle. In order to work that out, we would need to know the volumes of the water and the cube, and WHAT metal the cube is made of.
7 0
2 years ago
If a truck has the mass of 2,000 kilometres and a velocity of 35 m/s, what is the momentum
alexira [117]

Answer:

<h2>70,000 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 35

We have the final answer as

<h3>70,000 kg.m/s</h3>

Hope this helps you

5 0
2 years ago
Jeff wrote the following statement:
S_A_V [24]

Answer:

i think its the second one

Explanation:

simply because hes living by that theory wveryday that because his dads a good athlete then hell be one too

8 0
1 year ago
Read 2 more answers
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