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enot [183]
3 years ago
15

A damping force affects the vibration of a spring so that the displacement of the spring is given by y = e−4t(cos 2t + 3 sin 2t)

. Find the average val
Physics
1 answer:
astraxan [27]3 years ago
4 0

Answer:

Average velocity = dy/dt = 4sin2t(2t+3)-4cos2t(6t+1)e^-4t(cos 2t + 3 sin 2t).

Explanation:

Velocity is defined as the rate of change in displacement.

Velocity = change in displacement/time taken

Given the displacement of the string as;

y = e^−4t(cos 2t + 3 sin 2t).

To get the average velocity, we will find the derivative of the displacement with respect to time.

Using function of a function to solve this;

Let u = 4t(cos 2t + 3 sin 2t)... (1)

y = e^-u... (2)

Differentiating both functions with respect to their variables we have;

dy/du = -e^-u

du/dt is gotten using the product rule to have;

du/dt = 4t(-2sin2t+6cos2t)+4(cos2t+3sin2t)

Opening up the bracket we have;

du/dt = -8tsin2t+24tcos2t+4cos2t+12sin2t

Collecting like terms;

-8tsin2t+12sin2t+24tcos2t+4cos2t

du/dt = -4sin2t(2t-3)+4cos2t(6t+1)

dy/dt = dy/du × du/dt

dy/dt = -e^-u × -4sin2t(2t+3)+4cos2t(6t+1)

Substituting u = 4t(cos 2t + 3 sin 2t) into dy/dt, we will have;

dy/dt = -e^-4t(cos 2t + 3 sin 2t) × -4sin2t(2t+3)+4cos2t(6t+1)

dy/dt = 4sin2t(2t+3)-4cos2t(6t+1)e^-4t(cos 2t + 3 sin 2t).

The average velocity of the wave function therefore give us;

dy/dt = 4sin2t(2t+3)-4cos2t(6t+1)e^-4t(cos 2t + 3 sin 2t).

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The acceleration of a particle is directly proportional to the square of the time t. When t =0, the particle is at x =24 m. Know
AlexFokin [52]

Answer:

x(t) = ⅟₁₀₈t⁴ + 10t + 24

v(t) = ⅟₂₇t³ + 10

Explanation:

a(t) = C₁t²

velocity is the integral of acceleration

v(t) = ⅓C₁t³ + C₂

position is the integral of velocity

x(t) = (⅟₁₂C₁)t⁴ + C₂t + C₃

x(0) = 24 = (⅟₁₂C₁)0⁴ + C₂0 + C₃

C₃ = 24

x(6) = 96 = (⅟₁₂C₁)6⁴ + C₂6 + 24

         72 = 108C₁ + 6C₂

         C₂ = 12 - 18C₁

v(6) = 18 = ⅓C₁6³ + C₂

          18 = 72C₁ + C₂

          18 = 72C₁ + (12 - 18C₁)

           6 = 54C₁

           C₁ = 1/9

           C₂ = 12 - 18(1/9)

           C₂ = 10

4 0
3 years ago
The speed of propagation of electrical signals in a nerve cell depends on the diameter of the axon (nerve fiber). If the nerve c
gayaneshka [121]

Answer:

61 ms

Explanation:

Given that

Length of the nerve call connecting the spinal cord to your feet, s is 1.1 m

Speed of the impulse of the nerve, v = 18 m/s

Time taken by the nerve to travel the distance, t = ?

In solving this, we'd apply the very most basic formula in physics. Formula of speed, with respect to time and distance.

Speed, v = distance, s / time, t

time, t = distance, s / speed, v

time, t = 1.1 / 18

time, t = 0.061 s, converting to milliseconds, we have, time, t = 61 ms

6 0
3 years ago
A balloon rises at the rate of 8 feet per second from a point on the ground 12 feet from an observer. To 2 decimal places in rad
Hitman42 [59]

Answer:

\displaystyle \theta' =0.24\ rad/s

Explanation:

<u>Rate Of Change</u>

Let some variable y depend on time t. we can express y as a function of t as

y=f(t)

The instant rate of change of y respect to t is the first derivative, i.e.

y'=f'(t)

The balloon, the ground and the observer form a right triangle (shown below) where the height of the balloon y, the horizontal distance x, and the angle of elevation are related with the trigonometric formula

\displaystyle tan\theta =\frac{y}{x}

Since x is constant, we take the derivative with respect to time  by using the chain rule:

\displaystyle sec^2\theta \ \theta' =\frac{y'}{x}

Solving for \theta'

\displaystyle \theta' =\frac{y'}{xsec^2\theta}

Let's compute the actual angle with the initial conditions y=9 feet, x=12 feet

\displaystyle tan\theta =\frac{y}{x}

\displaystyle tan\theta =\frac{9}{12}=\frac{3}{4}

Knowing that

\sec^2\theta=1+tan^2\theta

\displaystyle \sec^2\theta=1+\left(\frac{3}{4}\right)^2

\displaystyle \sec^2\theta=\frac{25}{16}

The balloon is rising at y'=8 feet/sec, thus we compute the change of the angle of elevation:

\displaystyle \theta' =\frac{8}{12\ \frac{25}{16}}

\displaystyle \theta' =\frac{32}{75}\ rad/s

\boxed{\displaystyle \theta' =0.43\ rad/s}

6 0
4 years ago
The number of gallons of water in a storage tank at time t, in minutes, is modeled by w(t) = 25 − t2 for 0≤t≤5. At what rate, in
Kisachek [45]

Answer:

Rate of change of water will be -6 gallon/minute

Explanation:

We have given water in the tank as the function of time as

w(t)=25-t^2

We have to find the rate of change of water in the tank at t = 3 minute

For rate of change we have to differentiate both side

So \frac{dw}{dt}=0-2t

At t = 3 minute

\frac{dw}{dt}=0-2\times 3=-6gallon/minute

8 0
4 years ago
A 90kg mountain climber hangs from a nylon rope and streches it ny 25.0cm. if the rope was originally 30.0m long and it's diamet
bixtya [17]

Answer:

Explanation:

E = σ/ε = (F/A) / (ΔL/L)

E = (mg/(πd²/4) / (ΔL/L)

E = (4mg/(πd²) / (ΔL/L)

E = 4Lmg/(πd²ΔL)

E = 4(30.0)(90)(9.8)/(π(0.01²)0.25)

E = 1.35 x 10⁹ Pa  or 1.35 GPa

7 0
3 years ago
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