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Reika [66]
3 years ago
11

In the attached position versus time graph what is the magnitude of average velocity for the entire 19 seconds of the motion. An

swer in m/s and the number only to the
nearest 100th (ie. The second position after the decimal point.). Remind yourself of the definition of velocity.

Physics
1 answer:
evablogger [386]3 years ago
8 0

According to the plot, the positions at time <em>t</em> = 0 s and <em>t</em> = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is

v_{\rm ave} = \dfrac{-2\,\mathrm m - (-1\,\mathrm m)}{19\,\mathrm s} = -\dfrac1{19}\dfrac{\rm m}{\rm s}\approx \boxed{-0.05\dfrac{\rm m}{\rm s}}

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