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Bumek [7]
3 years ago
6

30 1 5 miles in 2 3 of an hour. What is the average speed, in miles per hour, of the car?

Mathematics
1 answer:
oee [108]3 years ago
6 0

Answer:

131.086

Step-by-step explanation:

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Helpppppppppppppppppppppppppp walk me thru
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Answer:

i think its a trapazoid

Step-by-step explanation:

8 0
2 years ago
In a sale, normal prices are reduced by 20%. Andrew bought a saddle for his horse in the sale. The sale price of the saddle was
pshichka [43]
The formula for this is: (sale price) / (1 - percentage)
Percentage have to be in decimal form, so divide percentage by 100 to get the decimal form.

220/(1-.20) = $275

The original price was $275. 
8 0
4 years ago
What is the value of x
djyliett [7]

Hey there!


Assuming #1 ….


x + 7x + x = 180°
REWORD

1x + 7x + 1x = 180°

COMBINE the LIKE TERMS

(1x + 7x + 1x) = 180°

8x + 1x = 180°

9x = 180°

DIVIDE 9 to BOTH SIDES

9x/9 = 180/9

CANCEL out: 9/9 because it equal 1

KEEP: 180/9 because it give you the x-value

NEW EQUATION: x = 180/9

SIMPLIFY IT!
x = 20
||||~~||||~~||||~~||||~~~||||~~||||~~||||~~||||~~~||||

Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
2 years ago
Read 2 more answers
In quadratic drag problem, the deceleration is proportional to the square of velocity
Mars2501 [29]
Part A

Given that a= \frac{dv}{dt} =-kv^2

Then, 

\int dv= -kv^2\int dt \\  \\ \Rightarrow v(t)=-kv^2t+c

For v(0)=v_0, then

v(0)=-kv^2(0)+c=v_0 \\  \\ \Rightarrow c=v_0

Thus, v(t)=-kv(t)^2t+v_0

For v(t)= \frac{1}{2} v_0, we have

\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\  \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\  \\ \Rightarrow kv_0t=2 \\  \\ \Rightarrow t= \frac{2}{kv_0}


Part B

Recall that from part A, 

v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\  \\ \Rightarrow dx=-kv^2tdt+v_0dt \\  \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\  \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a

Now, at initial position, t = 0 and v=v_0, thus we have

x=a

and when the velocity drops to half its value, v= \frac{1}{2} v_0 and t= \frac{2}{kv_0}

Thus,

x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\  \\ =- \frac{1}{2k} + \frac{2}{k} +a

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

- \frac{1}{2k} + \frac{2}{k} +a-a \\  \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}
7 0
3 years ago
Leon is building a square picture frame. The side of the frame is 495 millimeters long. If a meter of wood costs $7, how much wi
REY [17]

Answer:

3.465

Step-by-step explanation:

Also can you give brainliest to all of your questions bc it really hard to get brainliest and it be really nice you can choose who i dont really care but just please do it it helps a lot

3 0
3 years ago
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