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Flura [38]
3 years ago
7

What is f (0) for the function f (a) = 2a + 3

Mathematics
2 answers:
vovangra [49]3 years ago
3 0
F(0)= 2* 0 +3

=0+3
f(0)=3
Nikolay [14]3 years ago
3 0

Answer:

<h3>f(0) =3</h3>

Step-by-step explanation:

f (a) = 2a + 3\\\\f(0)=?

Substitute 0 for a in the given equation

f(0) = 2(0)+3\\\\f(0) = 0+3\\\\f(0) =3

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Solve using standard algorithm 57.03+2.08
Rom4ik [11]

Answer:

59.08

Step-by-step explanation:

6 0
3 years ago
The center of a circle is at (−3, 1) and its radius is 9.
pickupchik [31]

Answer:

Sorry but the correct answer is (x+3)2+(y−1)2=81

Step-by-step explanation:

Because the radius squared is the answer of the equation

4 0
3 years ago
50 points to the person that can answer this correctly:
a_sh-v [17]

Answer:

The answer is B. (4) Because a coeffecient is the number next to the letter.

8 0
3 years ago
Read 2 more answers
Find the volume of the<br> triangular prism.<br> 3.6 cm<br> 5.4 cm<br> 9 cm
MrMuchimi

Answer:

174.96cm2

Step-by-step explanation:

V=lbh

=3.6×5.4×9

=174.96cm2

I don't knowif you want it in milliliters or litres so here are both of them

milliliters = 174.96

litres = 0.17496

6 0
2 years ago
Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
4 years ago
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