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2 years ago

A)0.5 B)2.5 C)-0.5 D)-2.5

Mathematics

1 answer:

7nadin3 [17]2 years ago

5 0

Answer:

B)2.5

Step-by-step explanation:

When x = 3 the actual = 6

Residual = actual - predicted = 6 - 3.5 = 2.5

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Find the quotient of -85^2-27n+76 / -17n-19

bagirrra123 [75]

Answer:
5n-4

Explanation:
The given expression is:
$\frac{-85n^2-27n+76}{-17n-19}$

1- Take the negative as a common factor from both the numerator and the denominator. This will give us:
$\frac{-(85n^2+27n-76)}{-(17n+19)}$

2- Cancel out the negative sign (common factor) from the numerator and denominator. This will give us:
$\frac{(85n^2+27n-76)}{(17n+19)}$

3- Factor the numerator. This wil give:
$\frac{(5n-4)(17n+19)}{(17n+19)}$

4- Finally, cancel out the (17n+19) which common in both numerator and denominator. This will give us the final expression:
5n-4

Hope this helps :)

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2 years ago

What ordered pair is 5 units away from (-5,-3)

icang [17]

Answer:

(4, -3)

Step-by-step explanation:

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3 years ago

Read 2 more answers

15 points and BRAINLIEST John and his sister each bought a car in 2005. John's car cost $3,000 and is decreasing in value $150 p

nignag [31]

Answer:

Step-by-step explanation:

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2 years ago

Martha earned $180 during the summer doing chores. She bought 3 books worth $14 each using her chore money. How much money was l

Viktor [21]

Answer:

$138

Step-by-step explanation:

We can first turn the words into a mathematical equation by substituting words with the information we have:

Total earning - ( Price of three books)

$180 - (Price of one book x 3)

$180 - ($14 x 3)

Finally, after we have created the mathematical equation, we solve it!

$180 - ($14 x 3)

$180 - $42

$138

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2 years ago

A sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To

Vesnalui [34]

Answer:

(-3.07, 11.07)

Step-by-step explanation:

Given that a sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To test this, the writer used eighteen adult male volunteers. These volunteers were randomly divided into two groups of nine subjects each.

Group Group One Group Two

Mean 300.00 296.00

SD 8.00 6.00

SEM 2.67 2.00

N 9 9

The mean of Group One minus Group Two equals 4.00

standard error of difference = 3.333

df = 16

t = 1.2000

Margin of error = 3.3333* t critical = 3.3333*2.121

95% confidence interval of this difference: From -3.07 to 11.07

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2 years ago