The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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64=2*2*2*2*2*2=2⁶
B⁻³=1/64
1/B³=1/2⁶
B³=2⁶
B=∛2⁶=2⁶/³=2²=4
Answer: B=4
what do you need help with
PART - A : tent - 1 volume = 400 cubic ft
Tent -2 volume = 384 cubic ft.
PART - B : I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume
<u>Step-by-step explanation:</u>
PART - A:
tent 1 :
Base = 10 x 10ft
Height= 12 ft
Volume = (1/3) (10x 10) (12)
= (1/3) (100) (12)
= 400 cubic ft.
Tent 2:
Base = 12 x 12 ft
Height= 8 ft.
Volume = (1/3) (12 x 12) (8)
= 384 cubic ft.
PART - B:
I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume
This is the answer with the correct work.
