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polet [3.4K]
3 years ago
8

Simplify the Expression. Clear explanation of monomials appreciated - Thanks!

Mathematics
1 answer:
Nataly [62]3 years ago
7 0
I think the answer is .4m^7n^8

Uhh I don’t know how to give it a clear explanation but all I did was multiply them

-0.8•-0.5= .4

M^2•m^5=m^7

n•n^7=n^8

Hope this helps some.
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Jason agreed to make 12 payments of $38.50 to buy a new TV so far he has made Seven payments how much more money does Jason owe
Stolb23 [73]

Answer:

$192.50

Step-by-step explanation:

12*38.50=462

7*38.50=269.5

462-269.50=192.50

8 0
3 years ago
How can sums and differences of cubes be identified for factoring?
Ad libitum [116K]
The sum of cubes is given as:
a³ + b³ = (a + b)(a² - ab + b²)

Example for the sum of cubes:

64x³+y³ ⇒ This is the sum of cubes because each term; 64, x³, and y³ are cube numbers

By writing each term as an expression of cube numbers, we have:
(4x)³ + (y)³ ⇒ 64 is 4³
Use the factorization of the sum of cubes, we have:
(4x + y) ( (4x)²- 4xy + y²)
(4x + y) (16x² - 4xy + y²)

--------------------------------------------------------------------------------------------------------------

The difference of cubes can be factorized as:
(x³ - y³) = (x - y)(x² + xy + y²)

Example
(125x³ - 8y³) = (5x - 2y) ((5x)² + (5x)(2y) + (2y)²)
                     = (5x - 2y) (25x² + 10xy + 4y²)
7 0
3 years ago
FK+M=A-UK solve for K
Elanso [62]
FK+M=A-UK
FK-UK=A-M
(F-U)K=A-M
K=(A-M)/(F-U)
3 0
3 years ago
An apple has a mass of 150g and a volume of 100cm cubed find its density
BartSMP [9]
Divide <span>150:100 to find out what the density in g/cm3 is. So 150:100 = 1.5 g/cm3</span>
8 0
3 years ago
Which expression is equivalent to sqrt128x^5y^6/2x^7y^5 ? Assume x 0 and y &gt; 0.
kolbaska11 [484]

<u>Answer:</u>

\frac{8\sqrt{y} }{x}

<u>Step-by-step explanation:</u>

We are given the following expression and we are to simplify it:

\sqrt {\frac {128x^5y^6} {2x^7y^5} }

To make it easier to solve, we can also write this expression as:

\sqrt {\frac{128}{2} * \frac {x^5} {x^7} * \frac {y^6} {y^5}}

Now we will cancel out the like terms to get:

\sqrt {64*\frac{1} {x^2}*y }

Taking the square root of the terms to get:

8*\frac {1}{x} .\sqrt{y}

\frac{8\sqrt{y} }{x}

4 0
3 years ago
Read 2 more answers
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