1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Igoryamba
3 years ago
7

In an isolated system, the total heat given off by warmer substances equals the total heat energy gained by cooler substances. N

ow look at your answer to Question 5. What might have caused the difference you have reported? Even though this data was provided to you, think of the errors the student could have encountered when collecting the data.
Physics
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

The temperature of the cooler substance was close to the room temperature. Therefore, the system experienced less change

Explanation:

Generally, in a closed system containing two bodies at different temperatures, there is a flow of heat energy from the body at a higher temperature to the body at a lower temperature. The effect is more significant when there is a large temperature difference between the bodies. However, if the temperature difference is small or insignificant, the change will be less.

You might be interested in
find a magnitude of the force such that if the act at right angle there resultant is √10N but if the act of 50° the resultant is
Readme [11.4K]

Explanation:

Let magnitude of the two forces be x and y.

Resultant at right angle R1= √15N) and at

60 degrees be R2= √18N.

Now, R1 = √(x² + y²) = √15,

R2= √(x² + y² +2xycos50) = √18.

So x² + y² = 15,

and x² + y² + 1.29xy = 18,

therefore 1.29xy = 3,

y = 3/1.29x.

y = 2.33/x

Now, x2 + (2.33/x)2 = 15,

x² + 5.45/x² = 15

multiply through by x²

x⁴ + 5.45 = 15x²

x⁴ - 15x2 + 5.45 = 0

Now find the roots of the equation, and later y. The two values of x will correspond to the

magnitudes of the two vectors.

Good luck

7 0
4 years ago
A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1)
loris [4]
Elastic collision is when kinetic energy before = kinetic energy after

Ek= 1/2mv^2

total before
Ek=1/2(2)(2.2^2) = 4.84 J

total after
Ek= 1/2(2+4)(v^2) = 3v^2

Before = after
4.84=3v^2 | divide by 3
121/75 = v^2 | square root both sides
v=1.27 m/s
7 0
3 years ago
What is the wavelength of a wave with a frequency of 262 hz and a speed of 343 m/s
Tamiku [17]

Heya!!

For calculate wavelength, lets applicate formula:

                                                      \boxed{\lambda = V/f}

                                                   <u>Δ   Being   Δ</u>

                                            f = Frequency = 262 Hz

                                            v = Velocity = 343 m/s

                                             \lambda = Wavelenght = ?

⇒ Let's replace according the formula:

\boxed{\lambda = 343\ m/s / 262\ Hz }

⇒ Resolving

\boxed{\lambda = 1,3 \ m}

Result:

The wavelength is <u>1,3 meters.</u>

Good Luck!!

8 0
3 years ago
Read 2 more answers
To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeof
BlackZzzverrR [31]
<h2>Answer: 26,8 s</h2>

Explanation:

If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

V_{f}=V_{o}+at (2)

Where:

V_{f} is the final velocity of the plane (the takeoff velocity in this case)

V_{o}=0 is the initial velocity of the plane (we know it is zero because it starts from rest)

a=5m/s^{2} is the constant acceleration of the plane to reach the takeoff velocity

d=1800m is the distance of the runway

t is the time

Knowing this, let's begin with (1):

{V_{f}}^{2}=0+2(5m/s^{2})(1800m) (3)

{V_{f}}^{2}=18000m^{2}/s^{2} (4)

V_{f}=134.164 m/s (5)

Substituting (5) in (2):

134.164 m/s=0+(5m/s^{2})t (6)

Finding t:

t=26.8 s This is the time needed to take off

6 0
3 years ago
Describe the different types of objects found in the Universe
Tema [17]
There are asteroids, which are rocks that fly through the space, and meteors which are pretty much the same. The only difference is their sizes. There are also planets, big and small. The moon, the dwarf planet Pluto, and many more. There are probably thousands of other planets that we haven't quite yet discovered. Soon we will though. There are also billions of stars, such as the sun, and some others we don't have names for that form constellations.
Hope this helped!!
4 0
3 years ago
Other questions:
  • Pirates drag a treasure chest to the left across a sandy beach. In which direction does the treasure chest experience a friction
    8·1 answer
  • What is the power used if it took 2,000 j to move a box in 8 s?
    7·1 answer
  • A 2.0-kg object is lifted vertically through 3.00 m by a 150-N force. How much work is done on the object by gravity during this
    9·2 answers
  • Physics (Electricity)
    8·2 answers
  • A statement that the energy supplied to a system in the form of heat, minus the work done by the system, is equal to the change
    12·1 answer
  • Answer part (d) please
    10·2 answers
  • A ball is thrown eastward into the air from the origin (in the direction of the positive x-axis). The initial velocity is 60 i +
    13·1 answer
  • An object sits at the edge of a table top with a mass of 180 kg. It is connected by a magical physics thread to a mass of 250 kg
    7·1 answer
  • Two students are watching a person riding a skate board up and down a ramp. each student shares what they think about the energy
    12·1 answer
  • How would an object need to move in order for total distance traveled and displacement to be equal?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!