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jarptica [38.1K]
4 years ago
14

Which will ensure laboratory safety during the experiment? Check all that apply. using beaker tongs to handle the hot beaker rea

ding the thermometer accurately checking the beaker for chips prior to heating on the hot plate using a beaker instead of an Erlenmeyer flask turning off the hot plate after use
Physics
2 answers:
Aleks [24]4 years ago
7 0

Answer: • using beaker tongs to handle the hot beaker.

• checking the beaker for chips prior to heating on the hot plate.

• Turning off the hot plate after use

Explanation:

The options that will ensure laboratory safety during the experiment will be:

• using beaker tongs to handle the hot beaker.

• checking the beaker for chips prior to heating on the hot plate.

• Turning off the hot plate after use.

We should note that the beaker tongs are simply used in the holding of the beakers that have hot liquids in them. Also, it s vital for the hot plate to be turned off after its use so as to prevent accident.

jek_recluse [69]4 years ago
6 0

Answer:

first: a,c,e

second: d

Explanation:

i just did it

edge 2021

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PLEASE HELP! I'LL GIVE BRAINLEST​
erma4kov [3.2K]

Answer:

8.162

Explanation:

W=mg

  = 2.2 x 3.71

  = 8.162 N

5 0
3 years ago
A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if
diamong [38]

Answer:

I believe that the answer is d.

Explanation:

Because there is nothing to make the aircraft accelerate or decelerate, it is going to stay in constant motion with no acceleration.

3 0
4 years ago
Find the y-component of this<br> vector:
NARA [144]

Answer:

Dy = 49.01 [m]

Explanation:

The vertical component of the vector can be determined with the sine of the angle.

Dy = 92.5*sin(32)

Dy = 49.01 [m]

6 0
3 years ago
Electric current in electric bulb is 20 mA, what is the charge flowing through the filament in 4 sec
anzhelika [568]

Answer:

The charge flowing through the filament is 0.08C

Explanation:

I=20mA = 0.02A\\t= 4s\\

Plug your given values into the charge and current formula:

I=\frac{Q}{t} \\Q=I*t\\Q= (0.02A)(4s)\\Q= 0.08C

6 0
3 years ago
Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
noname [10]

Answer:

a)   I = 2279.5 N s , b) F = 3.80 10⁵ N, c)   I = 3125.5 N s  and d)  F = 5.21 10⁵ N

Explanation:

The impulse is equal to the variation in the amount of movement.

    I =∫ F dt = Δp

     I = mv_{f} - m v₀

Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero

   v_{f}² = V₀² - 2g y

   v_{f}² = 0 - 2 9.8 30.0

   v_{f} = √588

   v_{f} = 24.25 m/s

a) We calculate the impulse

   I = 94 24.25 - 0

   I = 2279.5 N s

b) Let's join the other expression of the impulse to calculate the average force

   I = F t

  F = I / t

  F = 2279.5 / 6 10⁻³

  F = 3.80 10⁵ N

just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n

c)     I = m v_{f} - m v₀

       I = 94 8 - 94 (-24.25)

       I = 3125.5 N s

d)     F = I / t

       F = 3125.5 / 6 10⁻³

       F = 5.21 10⁵ N

7 0
3 years ago
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