1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
7nadin3 [17]
3 years ago
14

One batch of fruit punch contains 1/3 quart grape juice and 1/5 quart apple juice. Colby makes 11 batches of fruit punch. How mu

ch grape juice did he use for 11​ batches?
Mathematics
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

3.66666666667

Step-by-step explanation:

If you multiply the number of batches he makes and the amount of grape juice he needs for every quart, you get and answer of 3.66666666667.

1/3 * 11= 3.66666666667

If you need to round the answer it would be 3.67

You might be interested in
The formula for the area of a triangle is 1/2bh=A. Which of the following is not a possible first step to rearrange this formula
yarga [219]

We want to put b alone on one side of the equation.

If we multiply by 1/2, we get 1/4bh = A/2. Not only did we not remove a variable from the left side, we made it even more complicated.

So the answer is A.

7 0
3 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
What is an equivalent expression for 3(x-12)? *<br> O<br> 3x-12<br> 3x+12<br> O<br> 3x-36<br> 3x+36
Doss [256]
The correct answer is
3x - 36
7 0
3 years ago
Read 2 more answers
By What Fraction Must ⅝ be divided to get 7/9​
weqwewe [10]

Answer:

I don't understand this Qu?estion

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Sarah, Dan &amp; Gavyn share some
gregori [183]

Answer:

$11.25

Step-by-step explanation:

45/4=11.25

5 0
3 years ago
Other questions:
  • An exterior angle of a triangle measures 125° and one of the remote interior angles measures 35°. The triangle must be
    9·2 answers
  • HELP ME WITH THIS QUESTION
    6·1 answer
  • What is the domain of F(x) = In(x)?
    5·2 answers
  • If a space ship travels 22,500 miles per hour, in 100 hours, it would have traveled 2.25 x 106 miles. true or false
    12·1 answer
  • Find the value of the "?"
    7·1 answer
  • Graph the solution...please helppp me
    7·1 answer
  • 248 miles per hour = meters per second
    8·2 answers
  • The area of a rectangular park is 3/5 square mile. The length of the park is 7/8 mile. What is the width of the park?
    9·1 answer
  • A 12 oz soda costs $1.25 in the vending machine. At that rate, how much would a<br> 48 oz soda cost?
    14·1 answer
  • Twice the square of a number is less than another number. Negating the square of that number and adding 5 causes
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!