Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
15/35 of her attempts were successful.
Answer: look at the ss :))
Step-by-step explanation:
Answer:
10.55% probability
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the CDs are chosen is not important. So we use the combinations formula to solve this question.
1 Bach CD, from a set of 4.
1 Beethoven CD, from a set of 6.
1 Brahms CD, from a set of 3.
1 Handel CD, from a set of 2.
So, D=144
4 CDs from a set of 4+6+3+2 = 15.
So, T= 1365
p= D/T= 144/1365 = 0.1055
10.55% probability that she will choose one by each composer
