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Romashka [77]
3 years ago
13

A ball is thrown upward from 3 feet iff the ground at an initial velocity of 64 feet per second. What is the maximum height the

ball reaches?
Mathematics
1 answer:
Elza [17]3 years ago
7 0

I found h max = 64 feet

Explanation: Ok...probably you can do this differently but I would try to find the vertex of the parabola describing the trajectory: 1) derive it: h ` ( t ) = 64 − 32 t 2) set derivative equal to zero: 64 − 32 t = 0 t = 64 32 = 2 sec 3) use this value of t into your trajectory: h ( 2 ) = h max 64 ⋅ 2 − 16 ⋅ 4 = 64 feet .

               

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Solve the following system of equations using Substitution: Submit your answer as an ordered pair. 2x−3y=32x-3y=32x−3y=3 x=y+2x=
exis [7]

9514 1404 393

Answer:

  (3, 1)

Step-by-step explanation:

We assume you want the solution to the system ...

  • 2x−3y=3
  • x=y+2

The second equation gives a nice expression for x, so we can use that in the first equation.

  2(y+2) -3y = 3 . . . . substitute for x in the first equation

  2y +4 -3y = 3 . . . . . eliminate parentheses

  -y = -1 . . . . . . . . . . . collect terms, subtract 4

  y = 1 . . . . . . . . . . . . multiply by -1

  x = 1 +2 = 3 . . . . . . substitute for y in the second equation

The solution is (x, y) = (3, 1).

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3 years ago
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Step-by-step explanation:

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8 0
3 years ago
El área del cuadrado que se forma sobre la hipotenusa del triángulo es...
exis [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

5 0
2 years ago
Help plz!!!
lara [203]

Answer with explanation:

→→→Function 1

f(x)= - x²+ 8 x -15

Differentiating once , to obtain Maximum or minimum of the function

f'(x)= - 2 x + 8

Put,f'(x)=0

-2 x+ 8=0

2 x=8

Dividing both sides by , 2, we get

x=4

Double differentiating the function

f"(x)= -2, which is negative.

Showing that function attains maximum at ,x=4.

Now,f(4)=-4²+ 8× 4-15

           = -16 +32 -15

          = -31 +32

          =1

→→→Function 2:

f(x) = −x² + 2 x − 3

Differentiating once , to obtain Maximum or minimum of the function

f'(x)= -2 x +2

Put,f'(x)=0

-2 x +2=0

2 x=2

Dividing both sides by , 2, we get

x=1

Double differentiating the function,gives

f"(x)= -2 ,which is negative.

Showing that function attains maximum at ,x=1.

f(1)= -1²+2 ×1 -3

   = -1 +2 -3

  = -4 +2

 = -2

⇒⇒⇒Function 1  has the larger maximum.

6 0
3 years ago
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