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PIT_PIT [208]
3 years ago
7

"Alexis, Becca, and Cindy do volunteer work at Adopt-a-Pet Animal Shelter. They worked a total of 285 hours at the shelter last

summer. Alexis worked 15 hours less than Becca. Cindy worked 4 more than twice as many hours as Becca."
show all work
Mathematics
2 answers:
Marina86 [1]3 years ago
5 0

Answer:

<h2>Alexis worked 59 hours, Cindy worked 152 hours and Becca worked 74 hours.</h2>

Step-by-step explanation:

Givens

  • They worked a total of 285 hours.
  • Alexis worked 15 hours less than Becca.
  • Cindy worked 4 more than twice as many hours as Becca.
  • Alexis is A.
  • Cindy is C
  • Becca is B

The expressions that model this problem would be

A+C+B=285

Because all together they work 285 hours.

A=B-15

Because Alexis worked 15 hours less than Becca.

C=4+2B

Because Cindy worked 4 hours more than twice Becca's hours

Now, we replace the last two expression in the first one

B-15+4+2B+B=285\\4B-11=285\\4B=285+11\\B=\frac{296}{4}=74

Then, we replace this value to find others

C=4+2B=4+2(74)=152

A=B-15=74-15=59

Therefore, Alexis worked 59 hours, Cindy worked 152 hours and Becca worked 74 hours.

Maslowich3 years ago
4 0

Answer:

Alexis = 59

Becca = 74

Cindy = 152

Step-by-step explanation:

a + b + c = 285

a = b - 15

c = 2b + 4

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