Question

"Alexis, Becca, and Cindy do volunteer work at Adopt-a-Pet Animal Shelter. They worked a total of 285 hours at the shelter last summer. Alexis worked 15 hours less than Becca. Cindy worked 4 more than twice as many hours as Becca."
show all work

Answer 1

Answer:

Alexis worked 59 hours, Cindy worked 152 hours and Becca worked 74 hours.

Step-by-step explanation:

Givens

• They worked a total of 285 hours.
• Alexis worked 15 hours less than Becca.
• Cindy worked 4 more than twice as many hours as Becca.
• Alexis is $A$.
• Cindy is $C$
• Becca is $B$

The expressions that model this problem would be

$A+C+B=285$

Because all together they work 285 hours.

$A=B-15$

Because Alexis worked 15 hours less than Becca.

$C=4+2B$

Because Cindy worked 4 hours more than twice Becca's hours

Now, we replace the last two expression in the first one

$B-15+4+2B+B=285\\4B-11=285\\4B=285+11\\B=\frac{296}{4}=74$

Then, we replace this value to find others

$C=4+2B=4+2(74)=152$

$A=B-15=74-15=59$

Therefore, Alexis worked 59 hours, Cindy worked 152 hours and Becca worked 74 hours.

Answer 2

Answer:

Alexis = 59

Becca = 74

Cindy = 152

Step-by-step explanation:

a + b + c = 285

a = b - 15

c = 2b + 4