The interval of the convergence is x < -3 or x > 3 if the series n 3^n/x^n goes infinitely.
<h3>What is convergent of a series?</h3>
A series is convergent if the series of its partial sums approaches a limit; that really is, when the values are added one after the other in the order defined by the numbers, the partial sums getting closer and closer to a certain number.
We can find the interval for the convergent by root test.
Like the Ratio Test, the root Test is used to determine absolute convergence (or not) with factorials, the ratio test is useful.
For the given series:

As the series goes infinitely, we can use root test.
By the root test, the convergence interval will be;
The interval of convergence is:
x < -3 or x > 3 we can write this as:
|x| < 3
Thus, the interval of the convergence is x < -3 or x > 3 if the series n 3^n/x^n goes infinitely.
Learn more about the convergent of a series here:
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The answer is 6√200, or on edge.
Answer:
Point A to point F and point I to point H would have the ratio of 2:1.
Answer:
, option B
Step-by-step explanation:
Complex numbers:
The most important relation that involves complex numbers is given by:

Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:
The solutions are:

We have to find the polynomial. All option have
. So

The correct answer is given by option b.
1. Reduce <span>3x2-6x-240 to x^2 - 2x - 80
2. Use " ^ " to indicate exponentiation
3. Factor </span>x^2 - 2x - 80 using completing the square:
x^2 - 2x + 1^2 - 1^2 - 80
(x+1)^2 - 1 - 80
(x+1)^2 - 81
(x+1)^2 - 9^2 = (x+1-9)(x+1 +9), or (x-8)(x+10)
Final answer, with all factors shown: 3(x-8)(x+10)