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2 years ago

What is the coefficient of the variable in the expression 6 − 4x − 8 + 2?

2 answers:

8 0

Remember, in mathematics, a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
So, the coefficient in 6-4x-8+2 would be -4.

Aleonysh [2.5K]2 years ago

5 0

Answer:

The coefficient of the variable in the expression 6 − 4x − 8 + 2 is -4.

Step-by-step explanation:

Consider the given expression, 6 - 4x - 8 + 2 .

We have to find the coefficient of variable terms.

Variable are those term that do not have any fixed value like x , y, z , etc. and coefficient of variable is the constant term along with it like 9a here a is variable and 9 is coefficient of variable a .

Constant terms are terms that have fixed values are constants. example 1 , 2, 3...etc.

For the given expression x is the variable and coefficient of variable is -4.

Thus, the coefficient of the variable in the expression 6 − 4x − 8 + 2 is -4.

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Multiply and simplify: 3a(4a2 – 5a + 12)

DochEvi [55]

3a(4a²-5a+12)

12a³-15a²+36a

~Hope this helped!~

3 0

3 years ago

You and four friends plan a surprise party. Each of you contributes the same amount of money m for food. Write an algebraic expr

professor190 [17]

Answer:

y=x/4

Step-by-step explanation:

i don't know if this is right but i hope this helps :)

8 0

3 years ago

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0

2 years ago

Bus A and Bus B leave the bus depot at 9 am. Bus A takes 30 minutes to complete its route once and bus B takes 40 minutes to com

kirill [66]

Answer:

11 am

Step-by-step explanation:

Bus A and Bus B leave the bus depot at 9 am.

Bus A takes 30 minutes to complete its route once

Bus B takes 40 minutes to complete its route once.

We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route

30 = 3 × 10

40 = 4 × 10

= 3 × 4 × 10

= 120 minutes

120 minutes after 9 am is

60 minutes = 1 hour

= 2 hours.

9am + 2 hours

= 11 am.

Therefore, they be back at the bus depot together at 11 am

4 0

3 years ago

What is the slope of this graph?

Lostsunrise [7]

Answer:

slope = -0.5

Step-by-step explanation:

7 0

3 years ago

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