Answer:
The parallel line would be y = 7
Step-by-step explanation:
If a line is parallel to x = -2, then it is a horizontal line. All horizontal lines can be written in the form of y = (a number). That number can be found as the y-coordinate in the ordered pair given.
y = 7
A. 49°, 59°, 72°
Because this is the only one that equals 180° which is the sum of a triangle
Answer:
adult $13 student $15
Step-by-step explanation:
A=adult S = student
9A + 4S = 177
1A + 4S = 73
Multiply the second by (-1)
9A +4S = 177
-1A -4S = -73
ADD BOTH (4S will be cancelled)
8A = 104
A = 13 ( Adult ticket = $13)
13 + 4S = 73
4S = 60
S = 15 ( student ticket $15)
The nth term of an AP = a + (n - 1)d
The pth term of the AP = a +(p - 1)d = 1/q
The qth term of the AP = a +(q - 1)d = 1/p
Sum of nth term = (n/2)(2a + (n - 1)d)
Sum for 20th term = (20/2)(2a + (20- 1)d) = 10(2a + 19d)
a +(p - 1)d = 1/q .....(a)
a +(q - 1)d = 1/p ......(b)
Equation (a) - (b)
a - a + (p - 1)d - (q - 1)d = 1/q - 1/p
pd - d -qd + d = (p - q)/pq
pd - qd = (p - q)/pq
(p - q)d = (p - q)/pq
Cancel out (p - q) from both sides
d = 1/(pq)
Recall a +(p - 1)d = 1/q .....(a)
a +(p - 1)(1/pq)= 1/q
a + (p - 1)/(pq) = 1/q
a = (1/q) - (p - 1)/(pq)
a = (p - (p - 1))/(pq)
a = (p - p + 1) / (pq)
a = 1/(pq)
a = 1/(pq), d = 1/(pq)
Recall sum of 20 terms:
10(2a + 19d)
10(2*(1/(pq)) + 19*(1/(pq)))
10 ( 2/(pq) + 19/(pq)) = 10* (2 + 19)/(pq)
= 10*21/(pq)
= 210 / (pq)
Sum of the 20 terms = 210/(pq)
Hope this explains it.
Answer:
C.
Step-by-step explanation:
Solve the equation by making a 
substitution to reduce the equation to a solveable form.
Exact Form: r
= 
, 
Decimal Form: 0, 0.18367346....
