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yulyashka [42]
3 years ago
11

HELP PLSSSSSSSSSSSSSS

Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0
9

Explanation: it’s next in the sequence
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What is the solution to the system? <br><br> (___,___)
Rina8888 [55]
For the first line we have a slope of (y2-y1)/(x2-x1)

(2--2)/(1--1)=4/2=2 so we have:

y=2x+b, now solve for b with either of the points, I'll use: (1,2)

2=2(1)+b

b=0 so the first line is:

y=2x

Now the second line:

(1-10)/(4--2)=-9/6=-3/2 so far then we have:

y=-3x/2+b, using point (4,1) we solve for b...

1=-3(4)/2+b

1=-6+b

b=7 so 

y=-3x/2+7 or more neatly...

y=(-3x+14)/2

...

The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...

2x=(-3x+14)/2

4x=-3x+14

7x=14

x=2, and using y=2x we see that:

y=2(2)=4, so the solution occurs at the point:

(2,4)


6 0
3 years ago
Is 11.5 rational or irrational
earnstyle [38]
11.5 is a rational number
4 0
3 years ago
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Step-by-step explanation:

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What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?
kvasek [131]

Answer:

The center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

\left(x-a\right)^2+\left(y-b\right)^2=r^2

here,

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  • center = (a, b)

Given the equation

\left(x-14\right)^2+\left(y+21\right)^2=64

\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}

\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2

comparing with the circle equation

\left(x-a\right)^2+\left(y-b\right)^2=r^2

Therefore, the center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

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2 years ago
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Serjik [45]

Answer:

I'm gemini

Step-by-step explanation:

I won't report u cause I need these points

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7 0
2 years ago
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