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3 years ago

1 (6x + 21) - 4x = 15

Mathematics

1 answer:

valina [46]3 years ago

7 0

Answer:

Step-by-step explanation:

It is seven since fist, you add like terms. then you divide ALL by three.

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Help someone that’s good at math need your help 15 points !

mylen [45]

Answer:

4x-4+3

Step-by-step explanation:

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2 years ago

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The diagram shows a dilation of segment AB. Which

Leni [432]

Answer: "The dilation is an enlargement". "point O is the center of dilation" and "The scale factor is 3"

this is correct i took the quiz

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3 years ago

jack has $7.55 of change in his pocket. if he has 4 more dimes than than nickels, and twice as many quarters as nickels, how man

dolphi86 [110]

Answer:

11 nickels, 15 dimes, 22 quarters

Step-by-step explanation:

number of nickels = x

number of dimes = x+4

number of quarters = 2x

- - - - - -

total of nickels = 5x cents

total of dimes = 10x + 40 cents

total of quarters = 50x cents

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755 = 5x + 10x + 40 + 50x

755 = 65x + 40

715 = 65x

x = 11

x+4 = 15

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8 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

Find the slope of the line that contains<br> the points (6, 8) and (2, 1).

yawa3891 [41]

Answer:

7/4 or 1.75

Step-by-step explanation:

Assuming this is a linear function, you can use the slope formula of change in y-values divided by change in x-values. Take your y-values (8 - 1), which is seven. Then take your x-values (6-2), which is equal to 4. Then your slope is just 7/4 or 1.75.

7 0

3 years ago

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