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Tom [10]
3 years ago
8

In a lab, the mass of object a is 52 kg. object a weighs

Physics
2 answers:
zaharov [31]3 years ago
6 0

Complete Question:

In a lab, the mass of object A is 52 kg. What does Object A weigh?

Answer:

weight = 509.6 Newton

Explanation:

The mass of an object is a scalar quantity. This is the amount of matter present in an object. Mass is measured by using a balance. The mass of an object does not change. it is the same for a particular object anywhere. The S.I unit for mass is kilograms . It can also be measured in grams too.

The weight of an object is a vector quantity. It has both magnitude and direction .The weight of an object is the force acting on it. The force might be due to gravity or a reaction force.  The S.I unit for weight is Newton. The weight is measured on a scale. The weight of an object can change with location.

The measured mass of object A is 52 kg . The weight can be computed as

weight = mass × gravitational acceleration

mass = 52 kg

gravitational acceleration = 9.8 m/s²

Weight = 52 × 9.8

weight = 509.6 Newton

aksik [14]3 years ago
5 0
If you are asking for the weight then the formula is F=mg where f is weight m is mass and g is acceleration due to gravity.m=52kg and g=9.8m/s2(the gravity of earth)
F=52*9.8=509.6
therefore the weight of the object is 509.6N
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Answer:

c. Momentum is the product of mass and velocity

e. Momentum is a vector quantity

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Explanation:

Linear momentum P

P = m .v

m =mass

v=Velocity

If mass take in kg and velocity is in m/s then momentum p will be in kg.m/s.

1. momentum is the product of velocity and mass.

2.Momentum is a vector quantity.

3.Momentum have kg.m/s unit.

So the following option are correct.

c. Momentum is the product of mass and velocity

e. Momentum is a vector quantity

g. Momentum has unit of kgm/s.

Note-

1.Joule is the unit of energy.

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A batter hits a pop fly, and the baseball (with a mass of 148 g) reaches an altitude of 265 ft. If we assume that the ball was 3
den301095 [7]

Answer:

The increase in potential energy of the ball is 115.82 J

Explanation:

Conceptual analysis

Potential Energy (U) is the energy of a body located at a certain height (h) above the ground and is calculated as follows:

U = m × g × h

U: Potential Energy in Joules (J)

m: mass in kg

g: acceleration due to gravity in m/s²

h: height in m

Equivalences

1 kg = 1000 g

1 ft = 0.3048 m

1 N = 1 (kg×m)/s²

1 J = N × m

Known data

h_2 = 265ft * \frac{0.3048m}{ft} = 80.77m

h_1 = 3ft * \frac{0.3048m}{ft} = 0.914m

m = 148g*\frac{1kg}{1000g} = 0.148kg

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Problem development

ΔU: Potential energy change

ΔU = U₂ - U₁

U₂ - U₁ = mₓgₓh₂ - mₓgₓh₁

U₂ - U₁ = mₓg(h₂ - h₁)

U_2 - U_1 = 0.148kg * 9.8 \frac{m}{s^2}*(80.77m - 0.914m) = 115.82 N * m = 115.82J

The increase in potential energy of the ball is 115.82 J

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