A 60KG WOMAN IS ON A LADDER 2 M ABOVE THE GROUND. WHAT IS HER POTENTIAL ENERGY
1 answer:
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Answer:
287.19 kg.m²
Explanation:
Given that :
The mass M of the horizontal platform = 111 kg
The radius R of the uniform disk = 1.67 m
mass of the person standing = 64.7 kg
distance of the person standing = 1.15 m
mass of the dog = 25.7 kg
distance of the dog = 1.35 m
Considering the moment of inertia of the object in the system; the net moment of the inertia can be expressed as:
=
=
= 287.19 kg.m²
Answer:
P2 = 128,205 pascal.
Explanation:
<u>Given the following data;</u>
Original Pressure, P1 = 100,000 pascals
Original Temperature, T1 = 273K
New Temperature, T2 = 350K
To find new pressure P2, we would use Gay Lussac' law.
<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>
Mathematically, Gay Lussac's law is given by;
Where;
- P represents pressure.
- T represents temperature.
- K is the constant of proportionality.
<em>Making P2 as the subject formula, we have;</em>
Substituting into the equation, we have;
P2 = 128205.13 ≈ 128205 pascal.
<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>