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3 years ago

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Light enters from air into diamond which has refractive index of 2.42 calculate the speed of light in diamond the speed of light

in air is 3*10^8 m/s

1 answer:

ELEN [110]3 years ago

8 0

The speed of light in diamond is $1.24\cdot 10^8 m/s$

Explanation:

The index of refraction of a material is equal to the ratio between the speed of light in vacuum and the speed of light in the material:

$n=\frac{c}{v}$

where

n is the index of refraction

c is the speed of light in vacuum

v is the speed of light in the material

In this problem, we have:

n = 2.42 is the refractive index of diamond

$c=3.0\cdot 10^8 m/s$ is the speed of light in vacuum

Solving for v, we find the speed of light in diamond:

$v=\frac{c}{n}=\frac{3\cdot 10^8}{2.42}=1.24\cdot 10^8 m/s$

Learn more about refraction:

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Ah electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

Advocard [28]

Answer:

The correct statement is "The electric field is directed toward the electron and has a magnitude of $\rm \dfrac{ke}{r^2}$ ".

Explanation:

According to Coulomb's law, the magnitude of the electric field due to a static point charge q at a point r distance away from it is given by

$\rm E = \dfrac{k|q|}{r^2}.$

k is the Coulmob's constant.

The direction of the electric field along the line joining the charge and the point where electric field is to be found and it is directed from positive charge to negative charge.

Conventionally, we assume a positive test charge placed at the point where electric field is to be found, the test charge has very small charge such that its charge does not affect the electric field due to the given charge.

The charge on the electron = -e.

The electric field due to an electron is given by

$\rm E = \dfrac{k|-e|}{r^2}=\dfrac{ke}{r^2}.$

The direction of this electric field is from positive test charge, placed at the point where electric field is to be found, towards the electron along the line joining the two.

Thus, the correct statement is "The electric field is directed toward the electron and has a magnitude of $\rm \dfrac{ke}{r^2}$ ".

5 0

3 years ago

A motorcycle has a mass of 2.50×10^2. A constant force is exerted on it for 60.0s. The motorcycles initial velocity is 6.00 m/s

Margarita [4]

The change in momentum is 5500 kg m/s

Explanation:

The change in momentum of an object is given by

$\Delta p = m(v-u)$

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have:

$m=2.50\cdot 10^2 kg$ (mass of the motorcycle)

$v=28.0 m/s$ (final velocity)

$u=6.0 m/s$ (initial velocity)

Therefore, the change in momentum is

$\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s$

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3 years ago

How can velocity change even if speed stays the same?

VARVARA [1.3K]

Answer:

the change of direction it's going

5 0

3 years ago

Why is the rotation system used in volleyball? Physics was the closest thing to PE

tankabanditka [31]

Answer:

A rotation occurs after every side out, which is when the receiving team gains the right to serve by winning a rally. ... The new serving team will rotate clockwise one spot. The purpose of this is to rotate all the players through the serving position. If you continue winning points, you stay in position.

3 0

3 years ago

Read 2 more answers

It is proposed that a spaceship might be propelled in the solar system by radiation pressure, using a large sail made of foil. W

Anvisha [2.4K]

Answer:

962291.57928 m²

Explanation:

$P_r$ = Pressure = $2\dfrac{I}{c}$ (full reflection)

I = Intensity = $\dfrac{P}{A}=\dfrac{P}{4\pi r^2}$

P = Power = $3.9\times 10^{26}\ W$

c = Speed of light = $3\times 10^8\ m/s$

M = Mass of Sun = $1.99\times 10^{30}\ kg$

m = Mass of ship = 1500 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Force of radiation is given by

$F_r=P_rA\\\Rightarrow F_r=2\dfrac{I}{c}\times A\\\Rightarrow F_r=2\dfrac{P}{4\pi r^2c} A$

This force will balance the gravitational force as stated in the question

$\dfrac{GMm}{r^2}=2\dfrac{P}{4\pi r^2c} A\\\Rightarrow A=\dfrac{4\pi cGMm}{2P}\\\Rightarrow A=\dfrac{4\times \pi\times 3\times 10^8\times 6.67\times 10^{-11}\times 1.99\times 10^{30}\times 1500}{2\times 3.9\times 10^{26}}\\\Rightarrow A=962291.57928\ m^2$

The area of the must be 962291.57928 m²

3 0

3 years ago