Answer:
x = 4
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
You have not provided the options to help us give you a specific answer.
If a quadratic function is written in the form
![f(x) = a {(x - h)}^{2} + k](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%20%7B%28x%20-%20h%29%7D%5E%7B2%7D%20%20%2B%20k)
Then (h,k) is the vertex, and 'a' is a constant.
For instance
![f(x) = 5 {(x - 1)}^{2} + 3](https://tex.z-dn.net/?f=f%28x%29%20%3D%205%20%7B%28x%20-%201%29%7D%5E%7B2%7D%20%20%2B%203)
has vertex at (2,3).
Also, an absolute function in the form
![g(x) = a |x - h| + k](https://tex.z-dn.net/?f=g%28x%29%20%3D%20a%20%20%7Cx%20-%20h%7C%20%20%2B%20k)
has vertex at (h,k).
This means
![g(x) = |x - 1| + 3](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%20%7Cx%20-%201%7C%20%20%2B%203)
also has vertex at (1,3).
I hope this explanation is helpful.
Given two points
, the slope of the line passing through the two points is
![m = \dfrac{A_y-B_y}{A_x-B_x}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cdfrac%7BA_y-B_y%7D%7BA_x-B_x%7D%20)
So, in your case, you have
![m = \dfrac{3-5}{-2-4} = \dfrac{-2}{-6} = \dfrac{1}{3}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cdfrac%7B3-5%7D%7B-2-4%7D%20%3D%20%5Cdfrac%7B-2%7D%7B-6%7D%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%20)
Every number that has 0 as last digit and isn't decimal number, can be divided by 10 without remainder. It works for both positive or negative numbers. If last digit is different from 0, you will have remainder equal to that last digit. Even number 0 is divisible by 10 (the answer is 0 of course) because its last and only digit is 0.