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GrogVix [38]
3 years ago
10

Jack reads 40 pages per hour. Dave reads at the rate of 3 5 of a pages per minute. Who reads faster? By how many pages per hour

faster?
Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

If dave is reading 3.5 then the answer is Dave and he read 170 more pages then Jack.

Step-by-step explanation:

3.5 pages x 60 minutes = 210 pages per hour

210

- 40= 170

170 + 40= 210 so thats how I know 170 is the answer.

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What is:
VikaD [51]

Answer:

1)50/100×32=16

2)50/100×60=30

3)25/100×16=4

4)25/100×36=9

5)25/100×60=15

6)25/100×100=25

This is the way to find a percentage if a number

Hope it helped!!

3 0
3 years ago
Read 2 more answers
How to solve an inequality
kirill [66]
Look on Google or ask your teacher
6 0
3 years ago
A shark weighs 405 kg and 68 grams a second shark weighs 324 kg and 75 g how much more does the first shark weigh in grams than
mariarad [96]

For this case we have to by definition:

1 kg equals 1000 grams

Shark 1:

405 kg and 68 grams

405 kg * \frac {1000 g} {1kg} = 405,000 grams

Thus, shark 1 weighs 405,068 grams.

Shark 2:

324 kg and 75 grams

324 kg * \frac {1000 g} {1 kg} = 324,000 grams

Thus, shark 2 weighs 324,075 grams.

Subtracting we have:

405.068 grams-324.075 grams = 80.993 grams

Thus, shark 1 weighs 80,993 grams more than the second.

Answer:

Shark 1 weighs 80,993 grams more than the second.

8 0
3 years ago
On a road, you take a random sample of the speed of 40 cars with a speed detector and determine that their average speed is 49 m
Bogdan [553]
B) because since the 40 cars averaged 49 mph it means that, that is the number that most cars have around the same speed of
4 0
4 years ago
Read 2 more answers
A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b
IrinaK [193]

Answer:

a. [ 0.454,0.51]

b. 599.472 ~ 600

Step-by-step explanation:

a)

Confidence Interval For Proportion

CI = p ± Z a/2 Sqrt(p*(1-p)/n)))

x = Mean

n = Sample Size

a = 1 - (Confidence Level/100)

Za/2 = Z-table value

CI = Confidence Interval

Mean(x)=410

Sample Size(n)=850

Sample proportion = x/n =0.482

Confidence Interval = [ 0.482 ±Z a/2 ( Sqrt ( 0.482*0.518) /850)]

= [ 0.482 - 1.645* Sqrt(0) , 0.482 + 1.65* Sqrt(0) ]

= [ 0.454,0.51]

b)

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)

Z a/2 at 0.05 is = 1.96

Samle Proportion = 0.482

ME = 0.04

n = ( 1.96 / 0.04 )^2 * 0.482*0.518

= 599.472 ~ 600

8 0
3 years ago
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