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2 answers:
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The distance between (-4,3,-6) and the origin is
The point is given as:
(x, y, z) = (-4,3,-6)
The origin is
(x, y, z) = (0,0,0)
The distance between the point and the origin is calculated as:
So, we have:
Evaluate
Hence, the distance between (-4,3,-6) and the origin is
Read more about distance at:
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All the points that are 6 units from (-1, 1) are those on the circle
(x+1)^2 +(y-1)^2 = 36
For y=0, the two points of interest satisfy
(x+1)^2 +1 = 36
(x+1)^2 = 35 . . . . . . subtract 1
x+1 = ±√35
x = -1±√35
The points you seek are (-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).
(x+1)^2 +(y-1)^2 = 36
For y=0, the two points of interest satisfy
(x+1)^2 +1 = 36
(x+1)^2 = 35 . . . . . . subtract 1
x+1 = ±√35
x = -1±√35
The points you seek are (-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).