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3 years ago

Which equation is the inverse of y = 2x^2 - 8?

Mathematics

1 answer:

evablogger [386]3 years ago

6 0

Answer: A

Step-by-step explanation:

$y=2x^2-8$

1. Swap x and y.

$x=2y^2-8$

2. Solve for the new y.

Add 8

$x+8=2y^2$

Divide by 2.

$\frac{x+8}{2}=y^2$

Extract the square root.

$\sqrt{\frac{x+8}{2} }=y$

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One of the fastest recorded speeds of a cheetah is 26.8 m/s. Approximately, what is this speed in kilometers per hour? [1 kilome

ra1l [238]

We know that 1 kilometer = 1,000 meters and that 1 hour = 60 minutes = 3,600 seconds

We have 26.8 meters per second so whats 26.8 meters in kilometers? there is 0.0268 kilometers in 26.8 meters. So now we need to multiply 0.0268 by 3,600 to get 96.48

So your answer would be 96.48 km/h

7 0

3 years ago

Using the Multiplication Property of -1

Papessa [141]

A. -(a+5)

Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:

-(a+5) * -1 = a+5

B. -(-x+31)

Apply the distributive property:

-(-x+31) becomes (- -x +31) which simplifies to (x+31)

multiply that by -1 to get -x+31

C. -(4x+12)

Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:

-(4x+12) * -1 = 4x+12

7 0

3 years ago

Abena has 1.3kg of apples and plenty of the other ingredients.

Sphinxa [80]

Answer:

No, she can't make for 15 people.

Step-by-step explanation:

For 15 people the mass of apple required is 1.375 kg.

She can only make 14 apple crumbles.

Please mark as brainliest

7 0

3 years ago

(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if $K(t)\neq 0$

Example of a second order nonlinear ODE:

$Y=-3K(Y){2}$

(D) Example of a nonlinear fourth order ODE:

$K^4(x) - \beta f [x, k(x)] = 0$

4 0

3 years ago

PLS HELP ME!!! which matrix represents the system of equations below {8x-9y+13z=11

Finger [1]

Answer:

The answer is below

Step-by-step explanation:

The system of equations:

8x-9y+13z=11

-8x-5y+5z=15

3x+4y-8z=-10

The equations can be represented in matrix form as:

AX = B

X = A⁻¹B

Therefore:

$\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] ^{-1}\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\$

$\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}\frac{1}{19} &-\frac{1}{19}&\frac{1}{19}\\-\frac{49}{380}&-\frac{103}{380}&-\frac{36}{95} \\-\frac{17}{380}&-\frac{69}{380}&-\frac{28}{95} \end{array}\right] \left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}-0.74\\-1.69\\0.13\end{array}\right] \\$

4 0

2 years ago