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3 years ago

How can i find the area of square and a rectangle

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

Multiply (length) times (width). For a square, both numbers will be the same.

Andre45 [30]3 years ago

7 0

Area of a Square - side times side. since each side of a square is the same, it can simply be the length of one side squared.

formula is:

A=S^2 or A=S*S *=times

Area of Rectangle - multiply the length times the width the

formula is:

A= L*W *= times

Hope it helps!!!!!!!!!!!!!:)

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3 years ago

What is the width of a rectangle with an area of 5/8 in. squared and a length of 10 inches?

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3 years ago

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3 years ago

Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1

ElenaW [278]

<h2>Hello!</h2>

The answers are:

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{6}{7}$ and $1\frac{5}{7}$

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

$\frac{5}{6}$ and $\frac{10}{12}$

We have that:

$\frac{10}{12}=\frac{5}{6}$

So, we have that the pairs of numbers

$\frac{5}{6}$

and

$\frac{5}{6}$

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

$\frac{6}{7}$ and $1\frac{5}{7}$

We have that:

$1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}$

So, we have that the pair of numbers

$\frac{6}{7}$

and

$\frac{12}{7}$

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

$\frac{3}{2},\frac{2}{3}$

and

$3\frac{1}{2},4\frac{4}{4}$

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{6}{7}$ and $1\frac{5}{7}$

Have a nice day!

3 0

3 years ago

Geometry!!!!!!!!!!!!!!!!!!!!

svlad2 [7]

Answer:

The two triangles are related by Side-Side-Side (SSS), so the triangles can be proven congruent.

Step-by-step explanation:

There are no angles that can be shown to be congruent to one another, so this eliminates all answer choices with angles (SSA, SAS, ASA, AAA, AAS).

This leaves you with either the HL (Hypotenuse-Leg) Theorem or SSS (Side-Side-Side) Theorem. We could claim that the triangles can be proven congruent by HL, however, we aren't exactly sure as to whether or not the triangles have a right angle. There is no indicator, and in this case, we cannot assume so.

This leaves you with the SSS Theorem.

8 0

3 years ago