<span>1.6m − 4.8 = −1.6m
<u>- 1.6m -1.6m
</u> -4.8 = -3.2m
<u>
</u>divide both sides by -3.2
m = 1.5</span>
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Answer:
13 4/9
Step-by-step explanation:
his average test score would be 82
you add together all the test scores
90 + 76 + 84 + 66 + 96 + 89 + 73 =574
and then you divide that number by how many scores there were
574 ÷ 7 = 82